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3 years ago

What is the percent by mass of magnesium sulfate in MgSO4 · 7H2O?

Chemistry

1 answer:

Degger [83]3 years ago

8 0

Answer: 48.83%

Explanation: Mass percent is the ratio of mass of the particular substance to the total mass of given compound.

${\text {mass percentage}}=\frac{\text{mass of }MgSO_4}{\text {total mass}}\times 100\%$

Mass of $MgSO_4$ = 120g

Mass of $MgSO_4.7H_2O$ = 246g

${\text {mass percentage}}=\frac{120g}{246g}\times 100\%=48.83\%$

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3 years ago

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vagabundo [1.1K]

Answer:

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Explanation:

According to the balanced equation:

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We can get the no. of moles of SO₃ produced:

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3 years ago

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Answer:

The correct answer is : $F^-$

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