Answer:
THE VOLUME OF THE NITROGEN GAS AT 2.5 MOLES , 1.75 ATM AND 475 K IS 55.64 L
Explanation:
Using the ideal gas equation
PV = nRT
P = 1.75 atm
n = 2.5 moles
T = 475 K
R = 0.082 L atm/mol K
V = unknown
Substituting the variables into the equation we have:
V = nRT / P
V = 2.5 * 0.082 * 475 / 1.75
V = 97.375 / 1.75
V = 55.64 L
The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L
1 mole contains = 6.02x10^23 atoms. 0.31mole contains = 0.31x6.02x10^23 = 1.8662x10^23.
<span>
If mass remains the same while the volume of a substance increases, the
density of the substance will decrease. The increase in the volume is called expansion, while the decrease in the volume is called contraction.
</span><span>The density measures how much matter (mass) there is in a given amount of space (volume). So, if the mass stays the same and the volume increases then there is the same amount of mass ad before but in bigger volume so the density is decreased. </span>
