Answer: c weak acid
Explanation:
The faster the rate of leaving proton, the more strong the acid is. Due to the resonance structure of benzoic acid, power of leaving proton is restricted
Please mark me the brainiest here is the answer
PSI-volts
<span>pipes-conductors </span>
<span>pump-battery </span>
<span>valve-switch </span>
<span>restriction-resistance </span>
<span>water meter-ammeter </span>
<span>water-electrons </span>
<span>high pressure output- + voltage </span>
<span>low pressure intake- -voltage </span>
<span>valve closed-open circuit </span>
<span>valve open-closed circuit </span>
<span>liters/second-amps</span>
If 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.
<h3>How to calculate concentration?</h3>
The concentration of a solution can be calculated by using the following formula;
Molarity = no of moles ÷ volume
According to this question, 5.0 grams of KCl is dissolved in 500 ml of water. The concentration is calculated as follows:
no of moles of KCl = 5g ÷ 74.5g/mol = 0.067mol
Molarity = 0.067mol ÷ 0.5L = 0.134M
Therefore, if 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.
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Work out each and total up. hope this helped.
<u>Answer:</u> No crystals of potassium sulfate will be seen at 0°C for the given amount.
<u>Explanation:</u>
We are given:
Mass of potassium nitrate = 47.6 g
Mass of potassium sulfate = 8.4 g
Mass of water = 130. g
Solubility of potassium sulfate in water at 0°C = 7.4 g/100 g
This means that 7.4 grams of potassium sulfate is soluble in 100 grams of water
Applying unitary method:
In 100 grams of water, the amount of potassium sulfate dissolved is 7.4 grams
So, in 130 grams of water, the amount of potassium sulfate dissolved will be 
As, the soluble amount is greater than the given amount of potassium sulfate
This means that, all of potassium sulfate will be dissolved.
Hence, no crystals of potassium sulfate will be seen at 0°C for the given amount.