Answer:
The question implies that force of friction is 2.1E4 N
F = M v^2 / R frictional force needed to supply this centripetal force
2.1E4 = M v^2 / R
v^2 = R * 2.1E4 / M
v^2 = 120 * 2.1E4 / 2.5E3 = 1200 * 2.1 / 2.5 = 1008 m^2/s^2
v = 31.7 m/s max speed of truck (about 70 MPH)
Momentum is a product of mass and the velocity of a body. The initial momentum is always equal to the final momentum during collisions between two bodies.
Therefore; M1U1 +M2U2 = M1V1+ M2V2, where m1 is the mass of tracey and m2 is the mass of jonas, while u is the initial velocity and v is the final velocity.
(32 ×0)+ (45×0) = (32 × v1) + (45 × 0.50)
0 = 32V1 + 22.5
32 V1 = -22.5
V1 = - 0.703 ( negative indicates difference in direction)
There, Tracey's speed will be 0.703 m/s
Answer:
218.5 N
Explanation:
In order for the sled to be in equilibrium along the vertical direction, the forces acting along this direction must be balanced. So the equilibrium equation is:
![N+F sin \theta - mg =0](https://tex.z-dn.net/?f=N%2BF%20sin%20%5Ctheta%20-%20mg%20%3D0)
where
N is the normal force
F = 50 N is the force that pulls the sled
is the angle between the force and the horizontal, so
is the component of F acting along the vertical direction
(mg) is the weight of the sled, with
m = 25 kg being the mass of the sled
g = 9.8 m/s^2 is the acceleration due to gravity
Solving the formula for N, we find
![N=mg-F sin \theta = (25 kg)(9.8 m/s^2)-(50 N)sin 32^{\circ}=218.5 N](https://tex.z-dn.net/?f=N%3Dmg-F%20sin%20%5Ctheta%20%3D%20%2825%20kg%29%289.8%20m%2Fs%5E2%29-%2850%20N%29sin%2032%5E%7B%5Ccirc%7D%3D218.5%20N)