<u>F = M A </u> (Newton's #2)
Force = (0.15 kg) (12 m/s²)
Force = (0.15 · 12) (kg·m/s²)
<em>Force = 1.8 Newtons</em>
The right answer for the question that is being asked and shown above is that: "1-4-3-2." (main sequence-->red giant-->supergiant-->white dwarf). Assume that all four H-R diagrams below represent a star in different stages of its life, after it starts to fuse hydrogen in its core.
Answer:
0.6 μC
Explanation:
C = capacitance of the capacitor = 100 x 10⁻¹² F
d = separation between the plates of capacitor = 1 mm = 1 x 10⁻³ m
E = Electric field = 6 x 10⁶ N/C
Q = Amount of charge
V = Potential difference
Potential difference is given as
V = E d
Amount of charge stored is given as
Q = CV
hence
Q = C E d
inserting the values
Q = (100 x 10⁻¹²) (6 x 10⁶) (1 x 10⁻³)
Q = 6 x 10⁻⁷ C
Q = 0.6 μC
120/60= 2m per s
220/55= 4m per s
720/80= 9m per s
Fastest run: 3rd run
Speed: 9m per s
Slowest: 1st run
Speed: 2m per s
Answer:
X2 - X2'=3.24×10⁻⁴m
Explanation:
Given Data
λ1=730nm=
λ2=640nm
d=0.61 mm
D=1.1 m
Distance of the second bright fringe from the central fringe is given by
Xn = = D x n x2 λ / d
X2 = 2 D λ1 / d
X2' = 2 D λ2 / d
Separation between the second bright fringes of the two wavelengths ( the separation between the second order fringes ) is ,
X2 - X2' = 2 D ( λ1 - λ2 ) / d
X2 - X2'= {2 x 1. 1 (730×10^-9 - 640×10^-9) }/ 0.61 x 10 ^-3
X2 - X2'=3.24×10⁻⁴m
