The O2 sensor<span> does produce its own voltage,</span>but<span> there are also two wires.</span>
TLDR: R=30 Ohms, I=2 Amps, 12V, 28V, 20V, respectively.
Alright, let’s break this down. There are three resistors in this circuit, meaning that we have to find the equivalent resistance. Luckily, they are all in parallel with one another; this means we can add the resistances together without having to do inverses like in a series problem. This means that the equivalent resistance, Req, would equal:
Req=R1 + R2 + R3
Req=6 + 14+ 10
Req=30 Ohms
This means that we could theoretically replace all three resistors with a 30 Ohm resistor and accomplish the same goal. Now, the entire voltage of the system would normally be reduced to zero after passing through the resistors - in this case, the 60 Vs would be lost after passing through 30 Ohms. This means we’re losing 2V/Ohm; now we can figure out how much we’re losing at each resistor.
By losing 2V per Ohm, we’re losing 12 V at the first resistor, 28 V at the second resistor, and 20 V at the third resistor.
Finally, we can calculate the current through the circuit; for a series circuit, the current remains the same. Using V=IR, we can find that:
V=IR
60 V = I(30 Ohms)
I = 2 Amps
The current passing through the circuit is 2 Amps.
Hope this helps!
Answer:
Sound waves travels fastest in solids.
Sound waves travels slowest in gases.
Explanation:
Sound waves travels fastest in solids.
Sound waves travels slowest in gases.
Answer:
the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Explanation:
Given the data in the question;
To determine the maximum intensity of an electromagnetic wave, we use the formula;
= 
ε₀cE
²
where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )
c is the speed of light ( 3 × 10⁸ m/s )
E is the maximum magnitude of the electric field
first we calculate the maximum magnitude of the electric field ( E )
E = 350/f kV/m
given that frequency of 60 Hz, we substitute
E = 350/60 kV/m
E = 5.83333 kV/m
E = 5.83333 kV/m × ( 
)
E = 5833.33 N/C
so we substitute all our values into the formula for intensity of an electromagnetic wave;
= ε₀cE²
= × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²
= 45 × 10³ W/m²
= 45 × 10³ W/m² × ( 
)
= 45 kW/m²
Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Answer:
D. the amount of water placed in jars
Explanation:
it was the same for all of the jars at the beginning
