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lilavasa [31]
2 years ago
14

A ball resting on a roof 75 meters high has 1000 Joules of gravitational potential energy. Calculate the mass of the ball. (SHOW

ALL WORK)
Physics
1 answer:
Arturiano [62]2 years ago
8 0

Answer:

The mass of the ball is 1.360 kilograms.

Explanation:

By Work-Energy Theorem, gravitational potential energy (U), in joules, is the product of weight of the ball (W), in newtons, and height (h), in meters. Please notice that weight is the product of the mass of the ball (m) and gravitational acceleration (g), in meters per square second. Then, the formula for the mass of the ball is:

m = \frac{U}{g\cdot h} (1)

If we know that U = 1000\,J, g = 9.807\,\frac{m}{s^{2}} and h = 75\,m, then the mass of the ball is:

m = \frac{U}{g\cdot h}

m = 1.360\,kg

The mass of the ball is 1.360 kilograms.

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You are on a 4 m high ladder and throw a ball upwards at 12 m/s. It lands on the ground below the ladder.
Gelneren [198K]

a) 2.75 s

The vertical position of the ball at time t is given by the equation

y= h+ut-\frac{1}{2}gt^2

where

h = 4 m is the initial height of the ball

u = 12 m/s is the initial velocity of the ball (upward)

g = 9.8 m/s^2 is the acceleration of gravity (downward)

We can find the time t at which the ball reaches the ground by substituting y=0 into the equation:

0 = 4 + 12t - 4.9 t^2

This is a second-order equation. By solving it for t, we find:

t = -0.30 s

t = 2.75 s

The first solution is negative, so we discard it; the second solution, t = 2.75 s, is the one we are looking for.

b) -15.0 m/s (downward)

The final velocity of the ball can be calculated by using the equation:

v=u-gt

where

u = 12 m/s is the initial (upward) velocity

g = 9.8 m/s^2 is the acceleration of gravity (downward)

t is the time

By subsisuting t = 2.75 s, we find the velocity of the ball as it reaches the ground:

v=12 -(9.8)(2.75)=-15.0 m/s

And the negative sign means the direction is downward.

7 0
3 years ago
What is the period if the block’s mass is doubled? note that you do not know the value of either m or k , so do not assume any p
Oksanka [162]

The period of the block's mass is changed by a factor of √2 when the mass of the block was doubled.

The time period T of the block with mass M attached to a spring of spring constant K is given by,

T = 2π(√M/K).

Let us say that, when we increased the mass to 2M, the time periods of the block became T', the spring constant is not changed, so, we can write,

T' = 2π(√2M/K)

Putting T = 2π(√M/K) above,

T' =√2T

So, here we can see, if the mass is doubled from it's initial value. The time period of the mass will be changed by a factor of √2.

To know more about time period of mass, visit,

brainly.com/question/20629494

#SPJ4

5 0
8 months ago
Name the physical quantity which changes contenously during uniform-circular motion.
kumpel [21]
The direction of the motion is constantly changing during
motion over any closed path, not only circular.
8 0
3 years ago
In the heat equation, what does c represent
Bingel [31]
Heat equation, Q = m.c.Δt
Here, c represents " the specific heat of the substance "

Hope this helps!
5 0
3 years ago
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What type of climate would be near cold ocean currents? PLEASE HELP QUICK!!
olya-2409 [2.1K]

Answer:

hot humid with lots of rain.

Explanation:

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