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lilavasa [31]
3 years ago
14

A ball resting on a roof 75 meters high has 1000 Joules of gravitational potential energy. Calculate the mass of the ball. (SHOW

ALL WORK)
Physics
1 answer:
Arturiano [62]3 years ago
8 0

Answer:

The mass of the ball is 1.360 kilograms.

Explanation:

By Work-Energy Theorem, gravitational potential energy (U), in joules, is the product of weight of the ball (W), in newtons, and height (h), in meters. Please notice that weight is the product of the mass of the ball (m) and gravitational acceleration (g), in meters per square second. Then, the formula for the mass of the ball is:

m = \frac{U}{g\cdot h} (1)

If we know that U = 1000\,J, g = 9.807\,\frac{m}{s^{2}} and h = 75\,m, then the mass of the ball is:

m = \frac{U}{g\cdot h}

m = 1.360\,kg

The mass of the ball is 1.360 kilograms.

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In a second order lever system the force ratio is 2.5, the load is at the distance of 0.5m from the fulcrum find distance of eff
Fynjy0 [20]

Answer:

1.25 m

Explanation:

From the question given above, the following data were obtained:

Force ratio = 2.5

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The distance of the effort from the fulcrum can be obtained as illustrated below:

Force ratio = Distance of effort / Distance of load

2.5 = Distance of effort / 0.5

Cross multiply

Distance of effort = 2.5 × 0.5

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1. What is the formula for the period of a pendulum and what is the main determining factor in its period?
Brut [27]

Answer:

T=2\pi \sqrt{\frac{L}{g}}

Explanation:

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The period of a pendulum is the time it takes for the pendulum to complete one oscillation.

The period of a pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

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From the formula, we see that the period of a pendulum does not depend on the mass.

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7 0
4 years ago
Nicole throws a ball at 25 m/s at an angle of 60 degrees abound the horizontal. What is the range of the ball?
just olya [345]

Answer:

the range or the ball is 48.81 m

Explanation:

given;

Nicole throws a ball at 25 m/s at an angle of 60 degrees abound the horizontal.

find:

What is the range of the ball?

solution:

let Ф = 25°

Vo = 25 m/s

<u>consider x-motion using time of fight: x = Vox * t</u>

where x = R = range

t =<u> 2 Voy </u>

      g

R =<u> Vo² sin (2Ф)</u>

           g

plugin values into the formula:

R = <u>(25)² sin (2*25) </u>

               9.81

R = 48.81 m

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