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lilavasa [31]
2 years ago
14

A ball resting on a roof 75 meters high has 1000 Joules of gravitational potential energy. Calculate the mass of the ball. (SHOW

ALL WORK)
Physics
1 answer:
Arturiano [62]2 years ago
8 0

Answer:

The mass of the ball is 1.360 kilograms.

Explanation:

By Work-Energy Theorem, gravitational potential energy (U), in joules, is the product of weight of the ball (W), in newtons, and height (h), in meters. Please notice that weight is the product of the mass of the ball (m) and gravitational acceleration (g), in meters per square second. Then, the formula for the mass of the ball is:

m = \frac{U}{g\cdot h} (1)

If we know that U = 1000\,J, g = 9.807\,\frac{m}{s^{2}} and h = 75\,m, then the mass of the ball is:

m = \frac{U}{g\cdot h}

m = 1.360\,kg

The mass of the ball is 1.360 kilograms.

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3 years ago
Please help on this question​
Yanka [14]

TLDR: R=30 Ohms, I=2 Amps, 12V, 28V, 20V, respectively.

Alright, let’s break this down. There are three resistors in this circuit, meaning that we have to find the equivalent resistance. Luckily, they are all in parallel with one another; this means we can add the resistances together without having to do inverses like in a series problem. This means that the equivalent resistance, Req, would equal:

Req=R1 + R2 + R3

Req=6 + 14+ 10

Req=30 Ohms

This means that we could theoretically replace all three resistors with a 30 Ohm resistor and accomplish the same goal. Now, the entire voltage of the system would normally be reduced to zero after passing through the resistors - in this case, the 60 Vs would be lost after passing through 30 Ohms. This means we’re losing 2V/Ohm; now we can figure out how much we’re losing at each resistor.

By losing 2V per Ohm, we’re losing 12 V at the first resistor, 28 V at the second resistor, and 20 V at the third resistor.

Finally, we can calculate the current through the circuit; for a series circuit, the current remains the same. Using V=IR, we can find that:

V=IR

60 V = I(30 Ohms)

I = 2 Amps

The current passing through the circuit is 2 Amps.

Hope this helps!

8 0
3 years ago
Through which media did sound waves travel the fastest and the slowest?
In-s [12.5K]

Answer:

Sound waves travels fastest in solids.

Sound waves travels slowest in gases.

Explanation:

Sound waves travels fastest in solids.

Sound waves travels slowest in gases.

7 0
3 years ago
In the United States, household electric power is provided at a frequency of 60 HzHz, so electromagnetic radiation at that frequ
grigory [225]

Answer:

the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Explanation:

Given the data in the question;

To determine the maximum intensity of an electromagnetic wave, we use the formula;

I = \frac{1}{2}ε₀cE_{max²

where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )

c is the speed of light ( 3 × 10⁸ m/s )

E_{max is the maximum magnitude of the electric field

first we calculate the maximum magnitude of the electric field ( E_{max  )

E_{max = 350/f kV/m

given that frequency of 60 Hz, we substitute

E_{max = 350/60 kV/m

E_{max = 5.83333 kV/m

E_{max = 5.83333 kV/m × ( \frac{1000 V/m}{1 kV/m} )

E_{max = 5833.33 N/C

so we substitute all our values into the formula for  intensity of an electromagnetic wave;

I = \frac{1}{2}ε₀cE_{max²

I = \frac{1}{2} × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²

I = 45 × 10³ W/m²

I = 45 × 10³ W/m² × ( \frac{1 kW/m^2}{10^3W/m^2} )

I = 45 kW/m²

Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

7 0
2 years ago
Vicky wanted to investigate water evaporation. She placed 50 mL of distilled water in three identical glass jars. She left one j
IgorC [24]

Answer:

D. the amount of water placed in jars

Explanation:

it was the same for all of the jars at the beginning

4 0
3 years ago
Read 2 more answers
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