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algol13
3 years ago
11

The transformer supplying power to an artist's light sculpture provides 9600-V AC when supplied by 120-V AC. If there are 100 tu

rns in the transformer's primary coil, how many turns are there in its secondary coil
Physics
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:

1.25 turns

Explanation:

From Transformer equation,

Ns/Np = Vs/Vp............................ Equation 1

Where Ns = Secondary turns, Np = Primary turns, Vs = secondary Voltage, Vp = Primary Voltage.

make Ns the subject of the equation  1

Ns = NpVs/Vp.......................... Equation 2

Given: Np = 100 turns, Vp = 120 V, Vs = 9600 V

Substitute into equation 2

Ns = 100(120)/9600

Ns = 1.25  turns.

Hence the are 1.25 turns in the  secondary coil = 1.25 turns

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Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height
noname [10]

Answer:

a)   I = 2279.5 N s , b) F = 3.80 10⁵ N, c)   I = 3125.5 N s  and d)  F = 5.21 10⁵ N

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The impulse is equal to the variation in the amount of movement.

    I =∫ F dt = Δp

     I = mv_{f} - m v₀

Let's calculate the final speed using kinematics, as the cable breaks the initial speed is zero

   v_{f}² = V₀² - 2g y

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   I = F t

  F = I / t

  F = 2279.5 / 6 10⁻³

  F = 3.80 10⁵ N

just before the crash the passenger jumps up with v = 8 m / s, let's take the moments of interest just when the elevator arrives with a speed of 24.25m/s down and as an end point the jump up to vf = 8 m / n

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A flock of ducks is trying to migrate south for the winter, but they keep being blown off course by a wind blowing from the west
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\vec v_{D/W}=\left(7.0\dfrac{\rm m}{\rm s}\right)(\cos\theta\,\vec\imath+\sin\theta\,\vec\jmath)

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\vec v_{W/E}=\left(5.0\dfrac{\rm m}{\rm s}\right)(\cos0^\circ\,\vec\imath+\sin0^\circ\,\vec\jmath)

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