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liberstina [14]
4 years ago
9

Please answer fast

Physics
1 answer:
shusha [124]4 years ago
3 0

Answer:

B 50kg

Explanation:

momentum =Mv

Then

momentum=M(v1+v2)=50(2*0.5)=50*1=50kg

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Galileo was the first scientist to do?
Shtirlitz [24]

Answer:

Discovered different planets.

Explanation:

8 0
3 years ago
In two or more complete sentences, describe the purpose and outcome of the Miller Urey experiment.
Rama09 [41]
<span>Miller Urey experiment's purpose was to test the chemical origin of life under the conditions supposed to be present on the early Earth. 
</span>The scientists Miller and Urey heated a mixture of water<span>, </span>ammonia<span>, </span>methane<span> and </span>hydrogen<span> in a sterile flask until it evaporated water to produce water vapour. </span><span>Electric sparks were passed through the mixture of </span>water vapour and gases, simulating lightning. The experiment was done during one week. After a week, the contents were analysed and Miller and Uray proved that <span>several organic compounds could be formed spontaneously by simulating the conditions of Earth's early atmosphere.</span> 
7 0
4 years ago
A Cessna aircraft has a liftoff speed of 120 km/h What minimum constant acceleration does the aircraft require to be airborne af
Lady_Fox [76]

Answer:

<h3>2.3125m/s²</h3>

Explanation:

Using the equation of motion v² = u²+2aS

v is the final velocity = 120km/hr

120km/hr = 120 * 1000/1 * 3600 = 33.3m/s

u is the initial velocity = 0m/s

a is the acceleration

S is the distance covered = 240m

On substituting the given parameters

33.3² = 0²+2a(240)

33.3² = 480a

1110 = 480a

a = 1110/480

a = 2.3125m/s²

Hence the minimum constant acceleration that the aircraft require to be airborne after a takeoff run of 240 m is 2.3125m/s²

4 0
4 years ago
What is the main difference between the Schrödinger model and the Bohr atomic model?
netineya [11]

Answer:

Schrödinger believed that electrons could only exist in orbits, but Bohr stated that electrons could be found anywhere in the atom

Explanation: I got it right on test

4 0
4 years ago
A 0.58 kg mass is moving horizontally with a speed of 6.0 m/s when it strikes a vertical wall. The mass rebounds with a speed of
Sunny_sXe [5.5K]

Answer:

5.8\; {\rm kg\cdot m \cdot s^{-1}}.

Explanation:

If the mass of an object is m and the velocity of that object is v, the linear momentum of that object would be m\, v.

Assume that the initial velocity of the mass is positive (6.0\; {\rm m\cdot s^{-1}}.) However, the direction of the velocity is reversed after the impact. Thus, the sign of the new velocity of the object would be negative- the opposite of that of the initial velocity. The new velocity would be (-4.0\; {\rm m\cdot s^{-1}}).

Thus, the change in the velocity of the mass would be:

\begin{aligned}& (\text{Change in Velocity}) \\ =\; & (\text{Final Velocity}) - (\text{Initial Velocity}) \\ =\; & (-4.0\; {\rm m\cdot s^{-1}}) - (6.0\; {\rm m\cdot s^{-1}}) \\ =\; & (-10\; {\rm m\cdot s^{-1})\end{aligned}.

The change in the linear momentum of the mass would be:

\begin{aligned} & \text{change in momentum} \\ =\; & (\text{mass}) \times (\text{change in velocity}) \\ =\; & 0.58\; {\rm kg} \times (-10\; {\rm m\cdot s^{-1}}) \\  =\; & (-5.8\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}.

Thus, the magnitude of the change of the linear momentum would be 5.8\; {\rm kg \cdot m \cdot s^{-1}}.

7 0
3 years ago
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