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4 years ago

Please answer fast

Physics

1 answer:

shusha [124]4 years ago

3 0

Answer:

B 50kg

Explanation:

momentum =Mv

Then

momentum=M(v1+v2)=50(2*0.5)=50*1=50kg

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an airplane accelerates down a runway at 3.20m/s2 for 32.8s until it finally lifts off the ground. Determine the distance travel

Butoxors [25]

from rest

dist = 1/2 accn timextime

=1/2 3.2 32.8x32.8

about 1.6x900 m/s ... 1350m

6 0

3 years ago

A 7.91g bullet is fired into a 1.52-kg ballistic pendulum initially at rest and becomes embedded in it. The pendulum subsequentl

Stella [2.4K]

Answer:

Explanation:

By law of conservation of momentum:

momentum before collision = momentum after collision

$m_{1} u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\\ m_1 = mass of bullet\\u_1 = initial speed of bullet\\m_2 = mass of pendulum\\u_2 = initial speed of pendulum\\v_1 = final speed of bullet\\v_2 = final speed of pendulum$

Initial speed of bullet is unknown whereas initial speed of pendulum will be zero as it was at rest.

Final speed of bullet and pendulum will be equal as bullet is embedded in pendulum and both moves together a vertical distance of 6.89cm.

Using third equation of motion:

$2 a S = v_{f}^2 - v_{i}^2$

where:

$a = -g = acceleration due to gravity = 9.8 m/s^2 ( for vertical motion)\\S = h = 6.89cm = Vertical height or distance it covers\\v_f = final speed = 0 (after covering 6.89cm)\\v_i = initial speed (unknown)$

Thus by placing values $v_i = 1.1620 m/s$

this speed will be final speed of collision for the calculation of initial speed of bullet.

Putting values:

$(7.91) * x + (1.52*10^3) * 0 = (7.91 + 1.52*10^3) * 1.162\\7.91 x = 1775.431\\x = 224m/s$

This 224m/s = 0.224Km/s which is closest to D

8 0

3 years ago

The specific heat capacity of ethanol is 2440J/kg °C. How many joules of energy will be required to heat 150g ethanol to 35°C if

m_a_m_a [10]

Answer:

Required energy = 4758 J

Explanation:

Specific heat capacity of a material is the amount of energy required to raise the temperature of one kilogram (kg) of that material through one degree Celsius (°C).

Given data :

Specific heat capacity = c = 2440 J/kg.°C

Mass = m = 150 g = 0.15 kg

Initial temperature = 22°C

Final temperature = 35°C

Change in Temperature = ΔT = 13°C

Energy = E = ?

Using the following formula and substituting the values, we get:

E = m × c × ΔT

E = 0.15 × 2440 × 13

E = 4758 J

8 0

3 years ago

Explain how the air balloon moves up and down.<br> Explain in terms of density

Fantom [35]

The heat in the air ballon from the flame will create moisture in the ballon and make it rise

4 0

3 years ago

A student uses a spring with a spring constant of 130 N/m in his projectile apparatus. When 56 J of

Triss [41]

Explanation:

$potentional \: energy \: = \frac{1}{2} k {x}^{2} \\ 56 = \frac{1}{2} \times 130 \times {x}^{2} \\ {x}^{2} = \frac{56}{65} \\ x = \sqrt{ \frac{56}{65} } meter$

plz..

mark it as a brilliant answer

4 0

3 years ago