All categories

3 years ago

A student uses a spring with a spring constant of 130 N/m in his projectile apparatus. When 56 J of

Physics

1 answer:

Triss [41]3 years ago

4 0

Explanation:

$potentional \: energy \: = \frac{1}{2} k {x}^{2} \\ 56 = \frac{1}{2} \times 130 \times {x}^{2} \\ {x}^{2} = \frac{56}{65} \\ x = \sqrt{ \frac{56}{65} } meter$

plz..

mark it as a brilliant answer

You might be interested in

In order to find the resultant of two vectors we must use the pythagoran therom, a +b2-2. Where the crepresents the resultant ve

nadezda [96]

Answer:

Furthermore, the Pythagorean theorem works when the two added vectors are at right angles to one another - such as for adding a north vector and an east vector.

8 0

3 years ago

The speed that light travels :

OLga [1]

I think it might be C.

4 0

3 years ago

Read 2 more answers

Two particles, one with charge -5.45 × 10^-6 C and one with charge 4.39 × 10^-6 C, are 0.0209 meters apart. What is the magnitud

Levart [38]

Explanation:

Given that,

Charge 1, $q_1=-5.45\times 10^{-6}\ C$

Charge 2, $q_2=4.39\times 10^{-6}\ C$

Distance between charges, r = 0.0209 m

1. The electric force is given by :

$F=k\dfrac{q_1q_2}{r^2}$

$F=9\times 10^9\times \dfrac{-5.45\times 10^{-6}\times 4.39\times 10^{-6}}{(0.0209)^2}$

F = -492.95 N

2. Distance between two identical charges, $r=0.0209\ m$

Electric force is given by :

$F=\dfrac{kq_3^2}{r^2}$

$q_3=\sqrt{\dfrac{Fr^2}{k}}$

$q_3=\sqrt{\dfrac{492.95\times (0.0209)^2}{9\times 10^9}}$

$q_3=4.89\times 10^{-6}\ C$

Hence, this is the required solution.

3 0

3 years ago

Which type of force absorbs shock in vehicles

Licemer1 [7]

Answer:

Vehicles typically employ both hydraulic shock absorbers and springs or torsion bars. In this combination, "shock absorber" refers specifically to the hydraulic piston that absorbs and dissipates vibration.

Explanation:

hope this helps

5 0

3 years ago

What is the length of a spring that has 450J of potential energy and a spring constant of 650N/m?

11111nata11111 [884]

Answer:

Δx = 1.2 m

Explanation:

The CHANGE of spring length) (Δx) can be found using PS = ½kΔx²

Δx = √(2PS/k) = √(2(450)/650) = 1.17669... ≈ 1.2 m

The actual length of the spring is unknown as it varies with material type, construction method, extension or compression, and other variables we have no clue about.

4 0

3 years ago