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3 years ago

A student uses a spring with a spring constant of 130 N/m in his projectile apparatus. When 56 J of

Physics

1 answer:

Triss [41]3 years ago

4 0

Explanation:

$potentional \: energy \: = \frac{1}{2} k {x}^{2} \\ 56 = \frac{1}{2} \times 130 \times {x}^{2} \\ {x}^{2} = \frac{56}{65} \\ x = \sqrt{ \frac{56}{65} } meter$

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The acrylic plastic rod is 200 mm long and 15 mm in diameter. if an axial load of 300 n is applied to it, determine the change i

Marta_Voda [28]

The acrylic plastic rod is 200 mm long and 15 mm in diameter. If an axial load of 300 N is applied to it, determine the change in its length and the change in its diameter.
. latd = -0.0002515 (15) = -0.00377 mm
elat = -Velong = -0.4(0.0006288) = -0.0002515
d = elong L = 0.0006288 (200) = 0.126 mm
elong = s
E = 1.697(106
)
2.70(109
) = 0.0006288
s = P
A = 300 p
4 (0.015)2 = 1.697 MPa
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3 years ago

While loading, a truck moves 10 meters west from point A to point B in 5 seconds. Then it moves back to point A in 5 seconds. Wh

Talja [164]

Answer:

2m/s

Explanation:

distance(s)=10m

time taken(t)=5s

Now,

Speed(s)=s/t

=10m/5s

=2m/s [•.• 10/5=2]

5 0

3 years ago

A bird flies directly into the windshield of a moving car. How does the FORCE exerted on the car compare to the FORCE exerted on

Anarel [89]

Answer:

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7 0

3 years ago

What is light emitting diode

Natali [406]

Answer:

A light emitting diode (a semiconductor diode which glows when voltage is applied.

8 0

3 years ago

By method of dimension show that the following equation are homogenous.

il63 [147K]

Answer:

Proof in explanataion

Explanation:

The basic dimensions are as follows:

MASS = M

LENGTH = L

TIME = T

Given equation is:

$H = \frac{u^2Sin^2\phi}{2g}$

where,

H = height (meters)

u = speed (m/s)

g = acceleration due to gravity (m/s²)

Sin Ф = constant (no unit)

So there dimensions will be:

H = [L]

u = [LT⁻¹]

g = [LT⁻²]

Sin Ф = no dimension

Therefore,

$[L] = \frac{[LT^{-1}]^2}{[LT^{-2}]}\\\\\ [L] = [L^{(2-1)}T^{(-2+2)}]$

[L] = [L]

Hence, the equation is proven to be homogenous.

ii)

$F = \frac{Gm_1m_2}{r^2}\\\\$

where,

F = Force = Newton = kg.m/s² = [MLT⁻²]

G = Gravitational Constant = N.m²/kg² = (kg.m/s²)m²/kg² = m³/kg.s²

G = [M⁻¹L³T⁻²]

m₁ = m₂ = mass = kg = [M]

r = distance = m = [L]

Therefore,

$[MLT^{-2}] = \frac{[M^{-1}L^{3}T^{-2}][M][M]}{[L]^2}\\\\\ [MLT^{-2}] = [M^{(-1+1+1)}L^{(3-2)}T^{-2}]\\\\$

[MLT⁻²] = [MLT⁻²]

Hence, the equation is proven to be homogenous.

8 0

3 years ago