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Fofino [41]
3 years ago
10

F(x)=3 over x+2-x-3 squared what is f(7)

Mathematics
1 answer:
dimaraw [331]3 years ago
7 0

<u>Answer:</u>

f(7)=\frac{-5}{3} or f(7)=-1.67

<u>Step-by-step explanation:</u>

We are given the following function of x and we are to find the value of f ( 7 ):

f ( x ) = \frac { 3 } { x + 2 } - \sqrt { x - 3 }

Substituting the given value (7) in the above function to get:

f(x)=\frac{3}{x+2}-\sqrt{x-3}

f ( 7 )= \ frac{3}{7+2}-\sqrt{7-3}

f(7) = \frac { 3 } { 9 } - \sqrt { 4 }

f(7)=\frac{1}{3}-2

f(7)=\frac{1}{3}-\frac{6}{3}

f(7)=\frac{-5}{3} or f(7)=-1.67

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angle EFG and angle GFH are a linear pair, m angle GFH= 2n+38 and m angle GFH=2n+38. what are m angle EFG and m angle GFH
motikmotik

Answer:

Part 1) m∠EFG=94°

Part 2) m∠GFH=86°

Step-by-step explanation:

we know that

m∠EFG+m∠GFH=180° -----> by linear pair (given problem)

we have

m∠EFG=3n+22

m∠GFH=2n+38

substitute the values

(3n+22)°+(2n+38)°=180°

Solve for n

(5n+60)=180

5n=180-60

5n=120

n=24

<em>Find the measure of angle EFG</em>

m∠EFG=3n+22

substitute the value of n

m∠EFG=3(24)+22=94°

<em>Find the measure of angle GFH</em>

m∠GFH=2n+38

substitute the value of n

m∠GFH=2(24)+38=86°

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A right triangle has a side of length 1 fourth and a hypotenuse of length 1 third. What is the length of the other side?
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Answer:

The other side = \frac{1}{12} units

Step-by-step explanation:

A right triangle has a side of length \frac{1}{4} units and;

the hypotenuse is \frac{1}{3}

According to Pythagorean theorem,

a² + b² = c² , where a and b are the two legs of a triangle and c is the hypotenuse.

Lets say a² = (\frac{1}{4}) ^2   and  c² = ((\frac{1}{3} )^2

b² = c² - a²

b² = \frac{1}{9} - \frac{1}{16} = \frac{1}{144}

So b = \sqrt{1/144} = \frac{1}{12} units.

So the other side = \frac{1}{12} units.

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