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3 years ago

76% of what number is 152?

Mathematics

2 answers:

Katarina [22]3 years ago

8 0

Answer:

$76\% \: of \: x = 152 \\ \frac{76}{100} \times x = 152 \\ 0.76 \times x = 152 \\ x = 152 \div 0.76 \\ x = 200$

So 76% of 200 is 152

Alexus [3.1K]3 years ago

6 0

Answer:

200

Step-by-step explanation:

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12h = 132 h= i need to know how to do that ^

Wittaler [7]

Answer:

h=11

Step-by-step explanation:

divide:

132/12h

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3 years ago

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Can somebody help me, please?

Sveta_85 [38]

Answer:

a. $x=10 \textdegree$

$m\angle L=39\textdegree\\\\m\angle M=51\textdegree\\\\m\angle K=90\textdegree$

Step-by-step explanation:

a. We know that angles in a triangle add up to 180°.

-The right angle triangle in the right triangle has a measure of 90°.

We can therefore equate our angles to 180° and solve for x;

$180=\perp\angle+(2x+19)+(3x+21)\\\\180=90+(2x+19)+(3x+21)\\\\90=5x+40\\\\5x=50\\\\x=10\textdegree$

Hence, the angle measure is x=10°

b. Having calculated the value of x from a above as x=10°, we can substitute to find the measures of the two acute angles:

$m\angle L=(2x+19)\textdegree\\\\=(2\times 10+19)\textdegree\\\\=39\textdegree\\\\m\angle M=(3x+21)\textdegree\\\\=(3\times 10+21)\textdegree\\\\=51\textdegree$

Since, the m∠K is a right angle, it measures 90°

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3 years ago

The sum of the three numbers in 2003,two of the numbers are 814 and 519 what is the third number

KonstantinChe [14]

Answer:

670

Step-by-step explanation:

2003-814=1189

1189-519=670

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3 years ago

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A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

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3 years ago

Choosing a career means you also need to think about your ________ ________ .

Sever21 [200]

Answer:

Life Path

Step-by-step explanation:

It's two words, and they are both of equal length. I hope that helps.

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4 years ago