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3 years ago

2/3y = 14/39 Please help me answer this.

1 answer:

3 0

Answer: y =13 because y represents how the number of how many times you multiply 2/3 to get to 14/39 so you divide 39 by 3 and get 13. now if you times 2 by 13, you don't get fourteen so I'm confused on that part and I might be wrong so I'm sorry if I'm wrong

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How many sentences are in 3 paragraph.

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There is 15 sentence in 3 paragraph

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2 years ago

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Use Trig to Solve this...If you dont know how to use trig in right triangles then DONT answer.

natita [175]

Answer:

3445!

Step-by-step explanation:

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2 years ago

8. The trapezoids are similar. The area of the smaller trapezoid is 131 m2. Find the area of the larger trapezoid to the nearest

kolbaska11 [484]

Answer:

$3,726\ m^{2}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x----> corresponding side of the larger trapezoid

y----> corresponding side of the smaller trapezoid

$z=\frac{x}{y}$

we have

$x=64\ m$

$y=12\ m$

substitute

$z=\frac{64}{12}$

step 2

Find the area of the larger trapezoid

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

x----> area of the larger trapezoid

y----> area of the smaller trapezoid

$z^{2}=\frac{x}{y}$

we have

$z=\frac{64}{12}$

$y=131\ m^{2}$

substitute

$(\frac{64}{12})^{2}=\frac{x}{131}$

$x=(\frac{4,096}{144})(131)$

$x=3,726\ m^{2}$

5 0

2 years ago

Consider the given right triangle. If angle B = 43 degrees and c = 26.7 meters, find a.

Nady [450]

Answer: Side a equals 19.5 metres

Step-by-step explanation: Consider the right angled triangle as shown in the picture attached. The triangle has been drawn with angle measuring 43 degrees, side c (line AB) measuring 26.7 m and side a (line CB) is yet unknown.

A right angled triangle can be solved if at least one side and an angle are available. In this question we shall apply the trigonometric ratios since we have one angle which shall be the reference angle (43°). Also we have an hypotenuse (the side facing the right angle) and an unknown side which is the adjacent (which lies between the right angle and the reference angle).

Cos B = Adjacent/Hypotenuse

Cos 43 = a/26.7

Cos 43 x 26.7 = a

0.7314 x 26.7 = a

19.52714 = a

a ≈ 19.5 (rounded to the nearest tenth)

Therefore the length of side a equals 19.5 metres.