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Tema [17]
3 years ago
14

Solve for x

Mathematics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer:

C. x = 1

Step-by-step explanation:

To solve this problem the best way is to use the quadratic formula. First make everything equal to 0 by adding 3 to both sides.

3x^2 - 6x + 3 = 0

The quadratic formula is: \frac{-b\pm\sqrt{b^2-4ac} }{2a}. Substitute the values of a, b, and c into the formula. Keep in mind:

  • a = 3
  • b = -6
  • c = 3

\frac{-(-6)\pm\sqrt{(-6)^2-4(3)(3)} }{2(3)} \rightarrow \frac{6\pm\sqrt{36-4(9)} }{6} \rightarrow \frac{6\pm\sqrt{0} }{6} \rightarrow \frac{1\pm0}{1} \rightarrow 1

Therefore, x = 1.

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The average of a list of 4 numbers is 90.0. A new list of 4 numbers has the same first 3 numbers as the original list, but the f
Thepotemich [5.8K]

Answer:

the average of this new list of numbers is 94

Step-by-step explanation:

Hello!

To answer this question we will assign a letter to each number for the first list and the second list of numbers, remembering that the last number of the first list is 80 and the last number of the second list is 96

for the first list

\frac{a+b+c+80}{4} =90

for the new list

\frac{a+b+c+96}{4} =X

To solve this problem consider the following

1.X is the average value of the second list

2. We will assign a Y value to the sum of the numbers a, b, c.

a + b + c = Y to create two new equations

for the first list

\frac{y+80}{4} =90

solving  for Y

Y=(90)(4)-80=280

Y=280=a+b+c

for the second list

\frac{y+96}{4} =X\\

\frac{280+96}{4} =X\\x=94

the average of this new list of numbers is 94

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