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Tema [17]
3 years ago
14

Solve for x

Mathematics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer:

C. x = 1

Step-by-step explanation:

To solve this problem the best way is to use the quadratic formula. First make everything equal to 0 by adding 3 to both sides.

3x^2 - 6x + 3 = 0

The quadratic formula is: \frac{-b\pm\sqrt{b^2-4ac} }{2a}. Substitute the values of a, b, and c into the formula. Keep in mind:

  • a = 3
  • b = -6
  • c = 3

\frac{-(-6)\pm\sqrt{(-6)^2-4(3)(3)} }{2(3)} \rightarrow \frac{6\pm\sqrt{36-4(9)} }{6} \rightarrow \frac{6\pm\sqrt{0} }{6} \rightarrow \frac{1\pm0}{1} \rightarrow 1

Therefore, x = 1.

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Use Pascal’s Triangle to determine the fifth term of the expansion of (x + 3)7
ValentinkaMS [17]

Answer:

2835x^5.

Step-by-step explanation:

By Binomial Theorem, T(r+1) = nCr * a^(r+1) * b^r.

Term 5 = 7C4 * x^5 * 3^4

= 35 * x^5 * 3^4

= 2835x^5.

7 0
3 years ago
What is 10c-3(5c-1)=2(4c+3)-5c
Eddi Din [679]
10c-15+3-8c-6+5c
7c-18 i think so
4 0
3 years ago
Solve 29 &lt; m^2+ 9/2<br> &lt; 45
german

Answer:29m^2+

405/2

Step-by-step explanation:

4 0
3 years ago
The final scores from the last five games of two basketball teams are given. Jumping Jackrabbits: 70, 65, 72, 80, 73 Leaping Liz
scoundrel [369]

Using the Mean Absolute Deviation(MAD) concept, it is found that:

a) The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

b) The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

<h3>What is the mean absolute deviation of a data-set?</h3>

  • The mean of a data-set is given by the sum of all observations divided by the number of observations.
  • The mean absolute deviation(MAD) of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations.
  • The mean absolute deviation represents the average by which the values differ from the mean.

Item a:

For the Jumping Jackrabbits, the mean and MAD are given by:

M = (70 + 65 + 72 + 80 + 73)/5 = 72

MAD = (|70 - 72| + |65 - 72| + |72 - 72| + |80 - 72| + |73 - 72|)/5 = 3.6.

For the Leaping Lizards, the mean and the MAD are given by:

M = (61 + 47 + 70 + 63 + 54)/5 = 59

MAD = (|61 - 59| + |47 - 59| + |70 - 59| + |63 - 59| + |54 - 59|)/5 = 6.8.

The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

Item b:

The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

More can be learned about the Mean Absolute Deviation(MAD) concept at  brainly.com/question/3250070

#SPJ1

4 0
2 years ago
Division facts for 2,5,10
docker41 [41]
10÷5=2. 10÷2=5. They are all a factor tree
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3 years ago
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