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1 year ago

PLSSSS HELPPPPPPP MEEEHHH ILL GIVE BRAINLY

Mathematics

1 answer:

dezoksy [38]1 year ago

4 0

Answer:

can u explain the question

Step-by-step explanation:

And I will answer asap

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leah wrote two different fractions with the same denominator.both fractions were less than 1.can their sum equal 1? can their su

dem82 [27]

Their sum can be both equal, or greater. If you have 3/8 and 6/8, you would get 9/8 or 1 and 1/8. Which is greater than 1. Also if you add 2/6 and 4/6, you get 6/6 or 1. proving that both are possible.

3 0

3 years ago

How long does a car traveling at 70 mph take to travel 88 miles, in hours

dybincka [34]

So,

Obviously, the car will travel 70 miles in one hour. So after one hour, the car will have traveled 70 miles. That leaves 18 miles.

The time it will take for the car to go another 18 miles will be 18 divided by 70.
$\frac{18}{70}$

Simplify.
$\frac{2*3*3}{2*5*7}$
$\frac{3*3}{5*7}$
$\frac{9}{35}$

Divide.
≈ 0.25714

So a car traveling at 70 mph will take approximately 1.25714 hours or 1.26 hours to travel 88 miles.

7 0

3 years ago

Solve: −5(x + 6) = 15

Sidana [21]

Answer:

-5x-30 = 15

or, -5x = 15+30

or, -5x = 45

or, x = 45/-5

therefore : x = -9

5 0

3 years ago

Read 2 more answers

A bike rental costs $8 per hour. Desiree has a coupon for 2 free hours. To find how many hours she can rent with $40, Desiree se

uysha [10]

$8(x-2)=40 \ \ \ (expand \ the \ brackets) \\
\downarrow \\
8x-16=40 \ \ \ (add \ 16) \\
\downarrow \\
8x=56 \ \ \ (divide \ by \ 8) \\
\downarrow \\
x=7$

4 0

2 years ago

Find LCM of: x2 - 9, 3x3 + 81

VikaD [51]

Answer:

$\boxed{\pink{\sf (x + 3) \ is\ the \ LCM . }}$

Step-by-step explanation:

Given two expressions ,

$\qquad (1)\: x^2 - 9 \\\\ \qquad (2)\:3x^3 + 81$

And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .

Factorising x² - 9 :- 

$= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ]$

Factorising 3x³ + 81 

$= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] }$

Hence we can see that (x+3) is common factor in both expressions.

Hence the LCM is ( x+3 ) .

8 0

2 years ago