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MrRa [10]
3 years ago
11

How do you identify the necessary information that is missing from a problem?

Mathematics
1 answer:
alexdok [17]3 years ago
6 0

Answer:

  It depends

Step-by-step explanation:

Identifying what is <em>not there</em> is always difficult. In the general case, the range of possibilities is infinite.

For relatively simple math problems, the problem statement usually gives a context and asks a question. The context will generally tell you the nature of the relationships that apply. The question will generally be answered by making use of the relationships to relate given information to requested information.

If a relationship involves 4 items, one is "unknown" (that you're asked to find), and only 2 are given, then you know the missing information is the remaining item in the relationship.

Often, you can work a problem a number of ways, so the information that is missing depends on the method you choose for working the problem.

___

In complicated multi-step problems, relationships may need to be developed, theorems proved, massive amounts of data examined, and more. In some cases, whole new areas of mathematics may need to be invented.

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Given one zero of the polynomial function, find the other zeros.
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

You need to use synthetic division to do all of these.  The thing to remember with these is that when you start off with a certain degree polyomial, what you get on the bottom line after the division is called the depressed polynomial (NOT because it has to math all summer!) because it is a degree lesser than what you started.

a.  3I   1   3   -34   48

I'm going to do this one in its entirety so you get the idea of how to do it, then you'll be able to do it on your own.

First step is to bring down the first number after the bold line, 1.

3I   1    3    -34    48

   _____________

      1

then multiply it by the 3 and put it up under the 3.  Add those together:

3I    1    3    -34    48

           3

----------------------------

      1     6

Now I'm going to multiply the 6 by the 3 after the bold line and add:

3I    1     3     -34     48                                                                                                    

             3      18

_________________

      1      6     -16

Same process, I'm going to multiply the -16 by the 3 after the bold line and add:

3I      1      3      -34      48

                3       18     -48

___________________

        1       6      -16       0

That last zero tells me that x-3 is a factor of that polynomial, AND that the depressed polynomial is one degree lesser and those numbers there under that line represent the leading coefficients of the depressed polynomial:

x^2+6x-16=0

Factoring that depressed polynomial will give you the remaining zeros.  Because this was originally a third degree polynomial, there are 3 zeros as solutions.  Factoring that depressed polynomial gives you the remaining zeros of x = -8 and x = 2

I am assuming that since you are doing synthetic division that you have already learned the quadratic formula.  You could use that or just "regular" factoring would do the trick on all of them.

Do the remaining problems like that one; all of them come out to a 0 as the last "number" under the line.

You got this!        

4 0
3 years ago
Write or draw to explain a way to find each sum 6+7, 8+4, 2+9
Aleonysh [2.5K]
The sum to 6+7 is 13 and the answer to 8+4 is 12 and the sum to 2+9 is 11
5 0
3 years ago
Read 2 more answers
Estimates of the number of cells in the human body vary over an order of magnitude.​ Indeed, the precise number varies from one
Amiraneli [1.4K]

Answer:

a) 2.00 × 10¹⁰;  b) 2.00 × 10¹³

Step-by-step explanation:

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\text{No. of cells} =\text{1 cm}^{3} \times\left( \dfrac{\text{1 m}}{\text{100 cm}}\right )^{3} \times \left (\dfrac{1 \, \mu \text{m} }{10^{-6}\,\text{ m}}\right )^{3} \times  \dfrac{\text{1 cell}}{\text{50 $\,\mu$m}^{3}} = \mathbf{2.00 \times 10^{10}} \textbf{ cells}

b) No. of cells in 1 L

\text{No. of cells} =  \text{1 L} \times \dfrac{\text{1000 cm}^{3}}{\text{1 L}} \times \dfrac{2 \times 10^{10} \text{ cells}}{\text{1 cm}^{3}} = \mathbf{2.00 \times 10^{13}} \textbf{ cells}

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3 years ago
What is the answer to -3 to the second power + 4.6 times -0.1
vagabundo [1.1K]
The answer is -9.46 yeah i think thats correct
8 0
3 years ago
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It’s area and surface area I need help
jeyben [28]

Answer:

379.3 meters squared

Step-by-step explanation:

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