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expeople1 [14]
3 years ago
13

Find p(2) and p(4) for the function p(x) = 6x4 + 4x3 – 3x2 + 8x + 15.

Mathematics
2 answers:
Ray Of Light [21]3 years ago
8 0

Answer:

all work is shown and pictured

gulaghasi [49]3 years ago
3 0

Answer:

p(2) =147 and p(4) = 1791

Step-by-step explanation:

We are given p(x)= 6x^4 + 4x^3 – 3x^2 + 8x + 15.

Now we need to find value of p(2) and p(4)

Put x =2,

p(2) = 6(2)^4 + 4(2)^3 – 3(2)^2 + 8(2) + 15

p(2) = 6(16)+4(8)-3(4)+8(2)+15

p(2) = 96+32-12+16+15

p(2) = 147

Now put x = 4

p(4) = 6(4)^4 + 4(4)^3 – 3(4)^2 + 8(4) + 15

p(4) = 6(256)+4(64)-3(16)+8(4)+15

p(4) = 1536+256-48+32+15

p(4) = 1791

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2 years ago
In ΔKLM, l = 48 inches, ∠K=55° and ∠L=46°. Find the length of k, to the nearest inch.\
s2008m [1.1K]

Given:

In  ΔKLM, l = 48 inches, ∠K=55° and ∠L=46°.

To find:

The length of k, to the nearest inch.

Solution:

According to Law of sine,

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In ΔKLM, using law of sine, we get

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On further simplification, we get

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Approximate the value to the nearest inch.

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