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2 years ago

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You discover some bones that have roughly %s as much carbon-14 in them as

2 answers:

Misha Larkins [42]2 years ago

7 0

Answer:

If a fossil bone is found to contain 1/8th as much Carbon-14 as the bone of a living animal, what is the approximate age of the fossil?(half-life of C-14 = 5800 years)

Explanation:

Dafna1 [17]2 years ago

4 0

Answer:

150 years i guess so? im nkt sure

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Which describe beta decay? check all that apply. in beta decay, a proton becomes a neutron and a positron. in beta decay, a neut

kiruha [24]

The statements which best describe beta decay are: option 1, 2 and 4.

<h3>What is a beta particle?</h3>

A beta particle can be defined as an isotope which typically undergoes radioactive decay through the emission of a radiation with a -1 charge.

Based on scientific information and records from radioactivity, we can infer that the statements which best describe beta decay are:

During beta decay, an atom of proton becomes a neutron and a positron.

During beta decay, an atom of neutron becomes a proton and an electron.

Beta decay releases energy.

Read more on beta decay here: brainly.com/question/12448836

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1 year ago

How is protenin in milk broken down in our digestive system

aliina [53]

Answer:

when we drink the milk the digestive system produce protease enzyme to break down the protein of milk.

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3 years ago

Ascorbic acid (H2C6H6O6; H2Asc for this problem), known as vitamin C, is a diprotic acid (Ka1= 1.0x10–5 and Ka2= 5x10–12) found

Igoryamba

Answer:

The concentrations are :

$[HAsc^-]=0.000702 M$

$[Asc^{2-}]=5.92\times 10^{-8} M$

The pH of the solution is 3.15.

Explanation:

$H_2Asc\rightleftharpoons HAs^-+H^+$ $K_{a1}=1.0\times 10^{-5}$

Initial

c 0 0

Equilibrium

c-x x x

$K_{a1}=\frac{[HAs^-][H^+]}{[H_2Asc]}$

$1.0\times 10^{-5}=\frac{x\times x}{(c-x)}$

$1.0\times 10^{-5}=\frac{x^2}{(0.050-x)}$

Solving for x:

x = 0.000702 M

$[HAsc^-]=0.000702 M$

$HAsc^-\rightleftharpoons As^{2-}+H^+$ $K_{a2}=5\times 10^{-12}$

Initially

x 0 0

At equilibrium ;

(x - y) y y

$K_{a2}=\frac{[As^{2-}][H^+]}{[HAsc^-]}$

$5\times 10^{-12}=\frac{y\times y}{(x-y)}$

$5\times 10^{-12}=\frac{y^2}{(x-y)}$

Putting value of x = 0.000702 M

$5\times 10^{-12}=\frac{y^2}{(0.000702 -y)}$

$y=5.92\times 10^{-8} M$

$[Asc^{2-}]=5.92\times 10^{-8} M$

Total concentration of $[H^+]=x+y=0.000702 M+5.92\times 10^{-8} M=7.0206\times 10^{-4} M$

The pH of the solution :

$pH=-\log[H^+]$

$pH=-\log[7.0206\times 10^{-4} M}=3.15$

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2 years ago

How to obtain drinking water from muddy water

arsen [322]

Answer:

by filtering it with filter paper

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2 years ago

Read 2 more answers

What is the molarity of a solution that contains 4.3 mol of acetic acid (C2H3O2) in 450. mL of solution?

lord [1]

Hey there !

Number of moles of solution: 4.3 moles

Volume in liters:

450.0 mL / 1000 => 0.45 L

Therefore:

Molarity = number of moles / volume of solution ( L)

Molarity = 4.3 / 0.45

=> 9.55 M

Hope that helps!

3 0

2 years ago