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Kryger [21]
3 years ago
14

I need help ASAP!!! Please i need help

Mathematics
2 answers:
tamaranim1 [39]3 years ago
4 0
The answer is the bottom left one :D

sattari [20]3 years ago
4 0
Equivalent fractions name the same amount, even though they have different sized paths<span />
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Can someone help me I don't get it
Rina8888 [55]
The answer is 63 degrees.
7 0
3 years ago
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Y = 5x + 8; if x = 3 helppp
Katyanochek1 [597]
Y = 5 x 3 + 8
y = 15 + 8
y = 23
3 0
3 years ago
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Use the Remainder Theorem to find the remainder for (2x^3-3x^2+6)/(x-1) and state whether or not the binomial is a factor of the
Bezzdna [24]

Answer:

Remainder= 5, and the binomial (x-1) is not a factor of the given polynomial.

Step-by-step explanation:

Given polynomial is (2x^3-3x^2+6) , we have to divide this with a binomial [tex}(x-1)[/tex] using remainder theorem.

Remainder theorem says if (x-a) is a factor then remiander would be f(a)

Therefore for (x-1), \ {we find}\  f(1)}

f(1)=(2\times 1^3-3\times1^2+6)\\1^3 =1\\1^2=1\\Substituting \ this \ above\\f(1)= (2-3+6)=5

Thus the remainder is 5 and since it is not 0 , so the binomial (x-1) is not a factor of the given polynomial.

6 0
3 years ago
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3/5x + 3 please help me out
Monica [59]
I’m sorry but there isn’t enough information here to answer anything. What does the equation equal?
5 0
3 years ago
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3. You roll two fair dice, a white one and a red one. (a) Find P(5 or 6 on the white die and an odd number on the red die) (b) F
Elden [556K]

Answer:

a. P(5 or 6 on the white die and an odd number on the red die) = 1/6

b. P(odd number on the white die and 5 or 6 on the red die) = 1/6

c. P(5 or 6 on the white die and an odd number on the red die) or P(odd number on the white die and 5 or 6 on the red die) = 1/3

Step-by-step explanation:

(a) P(5 or 6 on the white die and an odd number on the red die)

Step 1: P(5 or 6 on the white die) = 1/6 + 1/6 = 1/3

Step 2: P(odd number on the red die) = 1/2

Step 3: P(5 or 6 on the white die and an odd number on the red die) = 1/3 × 1/2 = 1/6

(b) Find P(odd number on the white die and 5 or 6 on the red die).

Step 1: P(odd number on the white die) = 1/2

Step 2: P(5 or 6 on the red die) = 1/6 + 1/6 = 1/3

Step 3: P(odd number on the white die and 5 or 6 on the red die) = 1/2 × 1/3 = 1/6

(c) Find P(5 or 6 on the white die and an odd number on the red die) or P(odd number on the white die and 5 or 6 on the red die).

Step 1: P(5 or 6 on the white die and an odd number on the red die) = 1/6

Step 2: P(odd number on the white die and 5 or 6 on the red die) = 1/6

Step 3: P(5 or 6 on the white die and an odd number on the red die) or P(odd number on the white die and 5 or 6 on the red die) = 1/6 + 1/6 = 1/3

7 0
2 years ago
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