Hello <span>Areyano7475
</span>
Question: T<span>he term drive app is used to describe applications stored on a computer true or false
Answer: False
Hope this helps
-Chris</span>
Answer:
import java.util.Scanner;
public class ArraysKeyValue {
public static void main (String [] args) {
final int SIZE_LIST = 4;
int[] keysList = new int[SIZE_LIST];
int[] itemsList = new int[SIZE_LIST];
int i;
keysList[0] = 13;
keysList[1] = 47;
keysList[2] = 71;
keysList[3] = 59;
itemsList[0] = 12;
itemsList[1] = 36;
itemsList[2] = 72;
itemsList[3] = 54;
/* Your solution goes here */
for ( i = 0; i < SIZE_LIST; i++){
if (keysList[i]>50){
System.out.println(itemsList[i] + " "); } }
System.out.println("");
}
}
Explanation:
I will explain the whole program flow.
- There are two arrays here
- The first list (keysList) contains the following elements:
13 element at first position of the array (0th index)
47 element at second position of the array (1st index)
71 element at third position of the array (2nd index)
59 element at fourth position of the array (3rd index)
- The other list (itemsList) contains the following elements:
12 element at first position of the array (0th index)
36 element at second position of the array (1st index)
72 element at third position of the array (2nd index)
54 element at fourth position of the array (3rd index)
- The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.
- Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
- So the program control enters the body of the loop.
- In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.
- In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
- So the output of the above program is:
72
54
The correct answer to this question is that Jeremy should use the F1 key.
In Word, the F1 key is the help button that will help Jeremy find any keyboard shortcut that he is looking for. After pressing F1, he can search for what he is looking for. A second option to find a keyboard short would be to perform a simple search on the Internet for what he is looking for.
Answer:
Distributed memory systems
Distributed memory systems use multiple computers to solve a common problem, with computation distributed among the connected computers (nodes) and using message-passing to communicate between the nodes.
Explanation:
Answer:
1 true 2 true 3 false 4 true
Explanation:
