Answer:
(a)The total number of outcomes where the sum is 9 or
greater than 9 is 10
(b)Total number of outcomes where the sum is odd = 18
(c)Total number of outcomes where the sum greater or equal to 9 and is
also odd = 6
Step-by-step explanation:
Here, Sample Space = { Sum of the two digits when two dices are thrown together}
or, S = {2,3,4,5,6,7,8,9,10,11,12}
(a) The number of ordered pairs where sum is 9 or greater than 9
= { sum is 9 , Sum is 10 , Sum is 11, Sum is 12}
= {(6,3)(3,6),(4,5)(5,4) , (5,5), (6,4),(4,6) , (6,5)(5,6), (6,6)}
Hence the total number of outcomes where the sum is 9 or
greater than 9 is 10
(b) The number of ordered pairs where sum is odd.
= { Sum is 3 , Sum is 5, Sum is 7, Sum is 9, Sum is 11}
= {(1,2)(2,1), (4,1)(1,4),(2,3)(3,2) , (6,1), (1,6),(5,2),(2,5),(4,3)(3,4) ,
(6,3)(3,6), (4,5)(5,4), (6,5),(5,6)} = 18
Hence total number of outcomes where the sum is odd = 18
(c) Intersection point refers the outcomes which have sum greater or equal to 9 and is odd
Here, the possible outcomes are = { Sum is 9 , Sum is 11}
={ (6,3)(3,6), (4,5)(5,4), (6,5),(5,6)} = 6
Hence total number of outcomes where the sum greater or equal to 9 and is also odd = 6
