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STALIN [3.7K]
3 years ago
5

Please help ASAP! Correct answer only! I need to finish this assignment today.

Mathematics
1 answer:
eimsori [14]3 years ago
3 0

Answer:

  0.4762

Step-by-step explanation:

There are 9C5 = 126 ways to choose 5 candidates to give speeches. There are (5C3)(4C2) = 60 ways that 3 of those candidates can be biology majors (and the other two can be non-biology majors). The probability of interest is ...

  60/126 ≈ 0.4762

__

nCk = n!/(k!(n-k)!)

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

15 kg

Step-by-step explanation:

Radius of a solid sphere : mass of a solid sphere

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Find the mass of a sphere of the same material of radius 5 cm

Radius of a solid sphere : mass of a solid sphere

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7 0
3 years ago
What is the surface area of this square pyramid
JulsSmile [24]

Answer:

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=> Option 4 (last one) is correct

Hope this helps!

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3 0
3 years ago
A personnel director in a particular state claims that the mean annual income is the same in one of the​ state's counties​ (Coun
Shalnov [3]

Answer:

a) The hypothesis that the mean annual income is the same could not be rejected. There is no enough evidence to claim they are different.

b) The critical values for this two-sided test are t=±1.711.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>(a) Identify the claim and state  H0  and  Ha. </em>

<em> Which is the correct claim​ below?</em>

<em>(b) Find the critical​ value(s) and identify the rejection​ region(s). </em>

<em> Enter the critical​ value(s) below.</em>

We have an hypothesis test on the difference of two means.

The null and alternative hypothesis are:

H_0: \mu_a-\mu_b=0\\\\H_a: \mu_a-\mu_b\neq 0

The claim of the alternative hypothesis is that the mean annual income is different in County A and County B.

The null hypothesis is that the mean annual income is equal in both counties.

The significance level is α=0.10.

The sample from County A has a mean of S40,400, a s.d. of $8,700 and a sample size of 18 residents.

The sample from County B has a mean of S39,200, a s.d. of $6,000 and a sample size of 8 residents.

The standard error of the difference of means is:

\sigma_d=\sqrt{\frac{\sigma_a^2}{n_a}+\frac{\sigma_b^2}{n_b}}=\sqrt{\frac{8700^2}{18}+\frac{6000^2}{8}}=\sqrt{8705000}=2950

The degrees of freedom are:

df=n_a+n_b-2=18+8-2=24

Then, the test statistic is:

t=\frac{\Delta M-\Delta \mu}{\sigma_d} =\frac{(40,400-39,200)-0}{2950} =\frac{1200}{2950}=0.407

For a statistic t=0.407, and df=24, the P-value is P=0.69. As the P-value is bigger than the significance level, the null hypothesis failed to be rejected.

If we would use the critial value approach, we would have to calculate the critical values for t, for df=24, two sided test and α=0.10.

The critical values, looking in a table, are t=1.711.

5 0
3 years ago
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