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nignag [31]
3 years ago
5

lign="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
WITCHER [35]3 years ago
4 0

Answer:

Step-by-step explanation:

What variable are you solving for?

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Can anybody help me pleasee I don't understandd
o-na [289]
Hello there.

6(8 - 2y) = 4y

To solve for this, we need to apply the Distributive Property to the left side of the equation. This property allows us to multiply the number outside of the parenthesis by all numbers inside of the parenthesis.

6(8 - 2y)
6(8) + 6(-2y)
48 - 12y

Now, let’s take a look at our equation.

-12y + 48 = 4y

To make things more simple, we’ll add 12y to both sides of the equation. This will cancel out -12y on the left side of the equation and will turn 4y on the right side of the equation into 16y.

Our new equation is:

16y = 48

Now all we need to do is divide both sides by 16 to solve for y.

16y / 16 = y
48 / 16 = 3

Our final answer and solution is:

Y = 3

I hope this helps!
4 0
3 years ago
How much more is 1.8 • 10^11 greater than 7.2 • 10^10
Rasek [7]

Answer:

1.8.10=1.80000000000

7.2.10=7.2000000000

Step-by-step explanation:

6 0
3 years ago
Find the first, fourth, and eighth terms of the sequence. A(n) = –5 • 3n–1
jeka94

Answer:

<h2>C. -5; -135, -10,935</h2>

Step-by-step explanation:

\text{Substitute}\ n=1,\ n=4\ \text{and}\ n=8\ \text{to}\ A(n)=-5\cdot3^{n-1}:\\\\A(1)=-5\cdot3^{1-1}=-5\cdot3^0=-5\cdot1=-5\\\\A(4)=-5\cdot3^{4-1}=-5\cdot3^3=-5\cdot27=-135\\\\A(8)=-5\cdot3^{8-1}=-5\cdot3^7=-5\cdot2,187=-10,935

6 0
3 years ago
Read 2 more answers
Is -5^2 equal to (-5)^2
gtnhenbr [62]
Yes, these 2 equations are equivalent
3 0
3 years ago
Read 2 more answers
Gravel is being dumped from a conveyor belt at a rate of 15 ft3/min, and its coarseness is such that it forms a pile in the shap
gayaneshka [121]

Answer:

0.13 ft/min

Step-by-step explanation:

We are given that

\frac{dV}{dt}=15ft^3/min

We have to find the increasing rate of change of height of pile  when the pile is 12 ft high.

Let d be the diameter of pile

Height of pile=h

d=h

Radius of pile,r=\frac{d}{2}=\frac{h}{2}

Volume of pile=\frac{1}{3}\pi r^2 h=\frac{1}{12}\pi h^3

\frac{dV}{dt}=\frac{1}{4}\pi h^2\frac{dh}{dt}

h=12 ft

Substitute the values

15=\frac{1}{4}\pi(12)^2\frac{dh}{dt}

\frac{dh}{dt}=\frac{15\times 4}{\pi(12)^2}

\frac{dh}{dt}=0.13ft/min

7 0
3 years ago
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