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nignag [31]
3 years ago
5

lign="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
WITCHER [35]3 years ago
4 0

Answer:

Step-by-step explanation:

What variable are you solving for?

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Express the product in simplest form.
Dmitry [639]

The product in simplest form is (x - 4)

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\frac{8}{2x+8} \times \frac{x^2-16}{4}

We have to find the product in simplest form

In the given expression,

2x + 8 = 2(x+ 4)

We know that,

a^2-b^2=(a+b)(a-b)

Therefore,

x^2-16 = x^2-4^2 =(x+4)(x-4)

Substitute these in given expression

\frac{8}{2(x+4)} \times \frac{(x+4)(x-4)}{4}

Cancel the common factors,

\frac{8}{2(x+4)} \times \frac{(x+4)(x-4)}{4} = x - 4

Thus the product in simplest form is (x - 4)

8 0
3 years ago
Erick paid a $75 registration fee to join the gym. He pays $15 each month.
liraira [26]

Answer:

$150

Step-by-step explanation:

Erick has to pay $15 per month so for 5 months he will have to pay $75 because 15 times 5 is 75. So $75 for registration fee + $75 for 5 months to use the gym give us $150

7 0
2 years ago
A midwestern music competition awarded 38 ribbons. The number of blue ribbons awarded was 1 less than the number of white ribbon
Artist 52 [7]
Starting from what I know (the difference between ribbons), I decided to go from the bottom and work my way up. I then noticed a pattern (each sum was three more of the previous one), and decided to keep my pattern of the three numbers but not have to do any major mental work and instead add three to the previous sum until I got to 38.

4 0
3 years ago
I need help with this for math,
liraira [26]
4. por.
5. non.
6. por.
7. non.
i hope they all right.

4 0
3 years ago
Kal is decorating the outside edge of a square
Grace [21]
Answer: Option A
Take not that this is a square bulletin board thus area = Length Times Base. Notice how it says its a square as well? thus telling us that each side is of equal length

Squaring the value N would give us the value of the one side of the board
5 0
3 years ago
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