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topjm [15]
3 years ago
13

Simplify the expression √((49x^4)/y^5 ). Show your work.

Mathematics
2 answers:
lesantik [10]3 years ago
7 0

Answer:

Step-by-step explanation:

\sqrt{\frac{49x^{4}}{y^{5}}}=\sqrt{\frac{7*7*x*x*x*x}{y*y*y*y*y}}\\\\=\frac{7*x*x}{y*y}\sqrt{\frac{1}{y}}\\\\=\frac{7x^{2}}{y^{2}}\sqrt{\frac{1}{y}}

Slav-nsk [51]3 years ago
5 0

Answer:7x^2 \sqrt{y} /y^3

Step-by-step explanation:

You might be interested in
AB=4x+3 and CD=24+5x find bc
madam [21]

Answer:

Step-by-step explanation:

1. use distribution factor

(4x+3)(24+5x)

4x times 24 = 96

4x times 5x = 20x

3 times 24 = 72

3 times 5x = 15x

2. combine like terms

96 + 72 = 168

15x + 20x = 35x

35x + 168 or 168 + 35x

I may be wrong please check my answer. I may have a lapse in my algebra, or I may have misunderstood the problem. But this is what I can give you to the best of my knowledge.

6 0
3 years ago
It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de
scoray [572]

Answer:

a) P(X

P(z

b) P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

P(z>-0.583)=1-P(Z

c) P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

X \sim N(72000,12000)  

Where \mu=72000 and \sigma=12000

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table and we got:

P(z

Part b

P(X>65000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>-0.583)=1-P(Z

Part c

P(X>100000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

5 0
3 years ago
WILL GIVE BRAINLIEST
kifflom [539]
Speed boat departed 1.75 hrs after steam boat1.8 hrs after speed boat departure, steam boat has sailed for a total: 1.8+1.75 = 3.55 hrssteam boat's speed is 36.8 km/hr, so it has traveled: 3.55*36.8 = 130.64 km
speed boat is 86.9 km behind steam boat. so it is 130.64-86.9 = 43.74 km from portspeed boat's speed = 43.74/1.8 = 24.3 km/hr

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