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Anna11 [10]
3 years ago
13

**HELP ASAP PLEASE!**

Physics
2 answers:
guapka [62]3 years ago
8 0
I think, according to Neil DeGrasse Tyson's Cosmos, that it would be either A. or B. That should eliminate the answers that I am pretty sure don't make sense. Though I am pretty sure it should be A...... 

P.S. You should watch Cosmos! It's pretty good!
Setler79 [48]3 years ago
7 0
They use a spectrograph so the answer would be B.
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Match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column. Use each word only o
Vlad [161]

Answer:

1. About a trillion comets are thought to be located far, far beyond Pluto in the Oort cloud.

2. The bright spherical part of a comet observed when it is close to the Sun is the coma .

3. A comet's plasma tail stretches directly away from the Sun.

4. A comet's nucleus is the frozen portion of a comet.

5. Particles ejected from a comet can cause a(n) meteor shower on Earth.

6. The Kuiper belt extends from about beyond the orbit of Neptune to about twice the distance of Neptune from the Sun.  

Explanation:

1. Oort cloud is a theoretical cloud of icy objects in interstellar space. Its inner limit begins about 2000-5000 AU from sun outer limit (about 100000-200000 AU) defines the boundary of solar system.  

Note: AU is the astronomical unit which is defined as the distance between the Sun and Earth.  

2. Comets are described as “dirty snowballs” which is a mixture of frozen gases and dust. When this snowball gets closer to the Sun, gas evaporates, and a fuzzy haze of gas and dust emerges. This fuzzy tail is the coma.

3. Dust and gas in the coma interact with the sunlight and the solar wind. Charged particles in the coma are caught up in the magnetic field of sun and flow away from the sun.  

4. Nucleus is the dirty snowball which consists of rock, dust and frozen gas.  

5. Meteor shower is a celestial event with number of meteors can be observed. Meteors are meteoroids that enters earth’s atmosphere with extremely high speeds.

6. Kuiper belt is a region beyond Neptune including dwarf planets and icy objects.  

5 0
3 years ago
A child and sled with a combined mass of 50.0 kg slide down a frictionless slope. if the sled starts from rest and has a speed o
Furkat [3]
            <span> Using conservation of energy

Potential Energy (Before) = Kinetic Energy (After)

mgh = 0.5mv^2

divide both sides by m

gh = 0.5v^2

h = (0.5V^2)/g

h = (0.5*2.2^2)/9.81

h = 0.25m

</span>
4 0
3 years ago
Read 2 more answers
According to Newton's 3rd Law, an object's momentum depends on it's velocity and mass. 4 dog-sled teams competed to see who coul
podryga [215]

Answer:

C.) Sled Team C 28 kg moving at 12m/s

I'm pretty sure.

7 0
3 years ago
How much weight can a man lift in the jupiter if he can lift 100kg on the earth.calculate​
Nuetrik [128]

Answer:

<h3><em>2</em><em>4</em><em>7</em><em>9</em><em> </em><em>Newton</em></h3>

<em>Sol</em><em>ution</em><em>,</em>

<em>Mass</em><em>=</em><em>1</em><em>0</em><em>0</em><em> </em><em>kg</em>

<em>Accele</em><em>ration</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>gravity</em><em>(</em><em>g</em><em>)</em><em>=</em><em>2</em><em>4</em><em>.</em><em>7</em><em>9</em><em> </em><em>m</em><em>/</em><em>s^</em><em>2</em>

<em>Now</em><em>,</em><em>.</em>

<em>weight = m \times g \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 100  \times 24.79 \\  \:  \:  \:  \:  \:  \:  = 2479 \: newton</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

5 0
3 years ago
A boxed 14.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an ang
adell [148]

Answer:

A boxed 14.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an angle of 36.9 ∘ above the horizontal. The monitor's speed is a constant 2.30 cm/s.

how much work is done on the monitor by (a) friction, (b) gravity

work(friction) = 453.5J

work(gravity) = -453.5J

Explanation:

Given that,

mass = 14kg

displacement length = 5.50m

displacement angle = 36.9°

velocity = 2.30cm/s

F = ma

work(friction) = mgsinθ .displacement

                      = (14) (9.81) (5.5sin36.9°)

                       = 453.5J

work(gravity)

= the influence of gravity oppose the motion of the box and can be pushing down, on the box from and angle of (36.9° + 90°)

= 126.9°

work(gravity) = (14) (9.81) (5.5cos126.9°)

                      = -453.5J

8 0
3 years ago
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