Answer:
x = (1 + sqrt(253))/14 or x = (1 - sqrt(253))/14
Step-by-step explanation:
Solve for x:
7 x^2 = x + 9
Subtract x + 9 from both sides:
7 x^2 - x - 9 = 0
x = (1 ± sqrt((-1)^2 - 4×7 (-9)))/(2×7) = (1 ± sqrt(1 + 252))/14 = (1 ± sqrt(253))/14:
Answer: x = (1 + sqrt(253))/14 or x = (1 - sqrt(253))/14
In this problem, you are asked to find the area of the
trapezoid. The formula in finding the area of the trapezoid is:
A = [(a + b)/2] x h
Where a = base 1
b = base
2
h =
height
Substituting the given measurements to the formula:
A = [(1.7 m + 6.7 m) / 2] x 5 m
A = (8.4 m / 2) x 5 m
A = 4.2 m x 5 m
A = 21 m^2
Therefore, the area of the trapezoid is 21 square meters.
Answer:
16 cm
Step-by-step explanation:
Suppose that x is the original width. If that original width is enlarged by a scale factor 5/2 that means that x is multiplied by 5/2 and after that multiplication we obtained new width, 40 cm.
Therefore,
x*(5/2) = 40
We multiply the equation by 2 and obtain:
x*5 = 40*2
5x = 80
Now we divide the equation by 5 and obtain:
x = 80/5
x = 16
We obtained that x, the original width was 16 cm
I got 0.3125 (i don’t know if that’s correct, because the question was hard for me to understand)
