Answer:
When the price of a good that complements a good decrease, then the quantity demanded of one increases and the demand for the other increases. When the price of a substitute good decreases, the quantity demanded that good increases, but the demand for the good that it is being substituted for decreases.
For the given sentences, the algebraic expressions are:
a) N = 110*c - 300
b) N = 12*b
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How to get the algebraic expressions?</h3>
For the first statement:
A 3-digit number, where the tens digit is c, can be written as:
N = 100*a + 10*c + b
Then the hundreds digit is a, and here we know that is 3 less than the tens digit, then:
a = c - 3
The ones digit is b, here we know that it is 0, then b = 0.
Replacing that in our number we get:
N = 100*(c - 3) + 10*c = 110*c - 300
N = 110*c - 300
That is the algebraic expression.
b) A two-digit number can be written as:
N = b*10 + a
Where b is the tens digit and a is the ones digit.
Here we know that the units digit is twice as bit as the tens digit, then:
a = 2b
Replacing that we get:
N = b*10 + a = b*10 + 2b = 12*b
N = 12*b
That is the algebraic expression.
If you want to learn more about algebraic expressions:
brainly.com/question/4541471
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Answer:
the first step is to subtract the 2W from each sides of the equal sides
Step-by-step explanation:
P=2L+2W
the first step is to subtract the 2W from each sides of the equal sides
P-2W=2L+2W-2W
P-2W=2L
Solve for d:
(3 (a + x))/b = 2 d - 3 c
(3 (a + x))/b = 2 d - 3 c is equivalent to 2 d - 3 c = (3 (a + x))/b:
2 d - 3 c = (3 (a + x))/b
Add 3 c to both sides:
2 d = 3 c + (3 (a + x))/b
Divide both sides by 2:
Answer: d = (3 c)/2 + (3 (a + x))/(2 b)
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Solve for x:
(3 (a + x))/b = 2 d - 3 c
Multiply both sides by b/3:
a + x = (2 b d)/3 - b c
Subtract a from both sides:
Answer: x = (2 b d)/3 + (-a - b c)
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Solve for b:
(3 (a + x))/b = 2 d - 3 c
Take the reciprocal of both sides:
b/(3 (a + x)) = 1/(2 d - 3 c)
Multiply both sides by 3 (a + x):
Answer: b = (3 (a + x))/(2 d - 3 c)
Answer:
45 because it is what I think
