All categories

3 years ago

Find three consecutive even integers whose sum is 72 solve

Mathematics

1 answer:

Alina [70]3 years ago

5 0

72/3 is 24 so 24+24+24 if you add one to one and take one away it’s the same so it becomes 23+24+25=72.

You might be interested in

The mean of 14 numbers is 49. Removing one of the numbers causes the mean to decrease to 43. What number was removed?

Mademuasel [1]

Answer:

126 was removed.

Step-by-step explanation:

The total before division took place was

Total = mean * 14

mean = 49

Total = 49 * 14

Total = 685

Now you subtract x from the total

685 - x

And divide by 13 [one number is missing]

(685 - x)/13

and the result = 43

(685 - x ) / 13 = 43 Multiply both sides by 13

685 - x = 43 * 13

685 - x = 559 Subtract 685 from both sides

- x = - 126 Multiply by - 1

x = 126

4 0

3 years ago

Explain how rotating a graph of an odd function 180° will affect its appearance.

ratelena [41]

The odd function is 2

5 0

3 years ago

Read 2 more answers

WHAT WOULD THIS BE!?!!!!!

victus00 [196]

Answer:

B 9

Step-by-step explanation:

Use the rule of exponents for a division. To divide two powers with the same base, write the same base and subtract the exponents.

$\dfrac{a^m}{a^n} = a^{m - n}$

Now do it with your numbers.

$\dfrac{3^4}{3^2} = 3^{4 - 2} = 3^2 = 3 \times 3 = 9$

Answer: B 9

7 0

3 years ago

evaluate the line integral ∫cf⋅dr, where f(x,y,z)=5xi−yj+zk and c is given by the vector function r(t)=⟨sint,cost,t⟩, 0≤t≤3π/2.

meriva

We have

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} \vec f(\vec r(t)) \cdot \dfrac{d\vec r}{dt} \, dt$

and

$\vec f(\vec r(t)) = 5\sin(t) \, \vec\imath - \cos(t) \, \vec\jmath + t \, \vec k$

$\vec r(t) = \sin(t)\,\vec\imath + \cos(t)\,\vec\jmath + t\,\vec k \implies \dfrac{d\vec r}{dt} = \cos(t) \, \vec\imath - \sin(t) \, \vec\jmath + \vec k$

so the line integral is equilvalent to

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (5\sin(t) \cos(t) + \sin(t)\cos(t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (6\sin(t) \cos(t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (3\sin(2t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \left(-\frac32 \cos(2t) + \frac12 t^2\right) \bigg_0^{\frac{3\pi}2}$

$\displaystyle \int_C \vec f \cdot d\vec r = \left(\frac32 + \frac{9\pi^2}8\right) - \left(-\frac32\right) = \boxed{3 + \frac{9\pi^2}8}$

7 0

2 years ago

Eve bought 6 3/4 pounds of clay for her sculpting project. She separated the clay into equal pieces that each weighed 1 1/8 poun

ValentinkaMS [17]

Sorry I can't help with the formula to work it into simplest form but the answer is 6 pieces of clay :(

6 0

3 years ago