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Veronika [31]
3 years ago
8

Identify the x- and y-intercepts for x=3.

Mathematics
1 answer:
amm18123 years ago
8 0
The answer is D, you don’t have enough information to find the y-int yet
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Find the surface area of the triangular prism shown below.
ira [324]

Answer:

150ft²

Step-by-step explanation:

surface area = (2×½×8×3)+(8+5+5)×7

= 24+126

= 159 ft²

7 0
3 years ago
1. tentukan hasil dari 243⅔?
Vesnalui [34]

Penjelasan langkah demi langkah:

1)

= 243^{\frac{2}{3} }\\= (\sqrt[3]{243})^2\\= 7^2\\= 49

2) √32 +3√18-2√50

= √16*2 +3√9*2-2√25*2

= 4√2 + 3(3√2)-2(5√2)

= 4√2 + 9√2-10√2

= 13√2-10√2

= 3√2

3) 1000 ⅔×64⅙

 = (\sqrt[3]{1000}) ^2 \times (2^6)^{1/6}  \\= 10^2 \times 2\\= 100 \times 2\\= 200

4) 3/4+√2

3/4+\sqrt{2} \\= \frac{3+4\sqrt{2} }{4 }

5) 2√3×√18

= 2√3×√9*2

= 2√3×3√2

= (2*3)(√3*√2)

= 6√6

6) 12/3+√3

= 4+√3

7) √1000—2√40

= 10 -2 (√4*10)

= 10-2(2√10)

= 10 - 4√10

8) 2- ¹+3-¹

= \frac{1}{2} + \frac{1}{3}\\ = \frac{3+2}{6}\\ = \frac{5}{6}

9)

\frac{5}{\sqrt{5} }\\ merasionalisasikan\\= \frac{5}{\sqrt{5} }\times \frac{\sqrt{5} }{\sqrt{5} }\\= \frac{5\sqrt{5} }{\sqrt{25} }\\= \frac{5\sqrt{5} }{5}\\ = \frac{\sqrt{5} }{1}

Jika pernyataannya opsional, penyebutnya adalah 1

10) 2√3×√18

= 2√3×√9*2

= 2√3×3√2

= (2*3)(√3*√2)

= 6√6

7 0
3 years ago
Find the equation of the line specified. The line passes through the points ( 5, 2) and ( 6, 4) a. y = 2x - 8 c. y = 2x + 12 b.
o-na [289]
<span>( 5, 2) and ( 6, 4)
slope m = (4-2)/(6-5) = 2

y = mx + b
b = y - mx
b = 2 - 2(5)
b = 2 - 10
b = -8

so now you have slope m = 2 and y intercept b = -8

equation
y = 2x - 8

answer
</span><span>a. y = 2x - 8</span>
4 0
3 years ago
Read 2 more answers
What is the hypothesis of the statement “If a triangle is scalene, then it contains no congruent sides”?
rusak2 [61]
Scalene has no congruent sides
5 0
3 years ago
Verify the following identity: (csc theta -cot theta )/(sec theta -1) A. sec theta B. cos theta C. cot theta D. sin theta
alexdok [17]

Answer:

C. cot theta

Step-by-step explanation:

(csc theta -cot theta )/(sec theta -1)

csc = 1/ sin

cot = cos / sin

sec = 1 / cos

Let x = theta

(1/ sin x -cos x / sin x )/(1/ cos x -1)

Getting a common denominator in the denominator and combining terms

(1- cos x)/ sinx  / ( 1 - cos x) / cos x

(1- cosx)      (1- cosx)

----------- ÷ ------------

sinx            cos x

Copy dot flip

(1- cosx)       cosx

----------- * ------------

sinx            1 -cos x

Cancel like terms

cos x / sin x

cos / sin = cot

cot x

cot theta

3 0
3 years ago
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