Write an algebraic expression from the following
1 answer:
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1. The range of a function is the set of all values that f can produce for all the x-es in the domain.
2. If we are given the graph, in order to find the range, we project the graph into the y axis. Informally, we draw the "shadow" of the graph into the y axis as in the FIGURE atached.
3. The range is <span>D || {y | −5 ≤ y ≤ −1}</span>
2. If we are given the graph, in order to find the range, we project the graph into the y axis. Informally, we draw the "shadow" of the graph into the y axis as in the FIGURE atached.
3. The range is <span>D || {y | −5 ≤ y ≤ −1}</span>
Answer:
The absolute change in the height of the water is 9.5 inches
Step-by-step explanation:
Given
--- length
--- width
--- height
--- the volume removed
Required
The absolute change in the height of the water
First, calculate the base area (b):
The height of the water that was removed is:
<em /><em> i.e. the volume of the water removed divided by the base area</em>
The absolute change in height is:
The picture in the attached figure
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is
4x²
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is
4x²