1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maw [93]
2 years ago
7

Name a line by any two points on the line, or a lowercase script letter.

Mathematics
1 answer:
Finger [1]2 years ago
7 0

Answer:

Step-by-step explanation: A    B

Lines can be named using any two points on the line or using a single cusive lowercase letter.

You might be interested in
write 700/200 as a terminating decimal. then describe two methods for converting a mixed number to a decimal
zhuklara [117]
\frac{700}{200}=\frac{7}{2}\\\\\#1\\\frac{7}{2}=3\frac{1}{2}=3\frac{5}{10}=3.5\\\\\#2\\\frac{7}{2}=\frac{6+1}{2}=\frac{6}{2}+\frac{1}{2}=3+\frac{1}{2}=3+0.5=3.5\\\\\underline{0.5}\\1:2\\\underline{0}\\10\\\underline{10}\\R=0

5 0
2 years ago
Thanks for helping if ya did
finlep [7]

Answer:

A

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A company compiles data on a variety of issues in education. In 2004 the company reported that the national college​ freshman-to
nasty-shy [4]

Answer:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

Step-by-step explanation:

For this case we know that we have a sample of n = 500 students and we have a percentage of expected return for their sophomore years given 66% and on fraction would be 0.66 and we are interested on the distribution for the population proportion p.

We want to know if we can apply the normal approximation, so we need to check 3 conditions:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

And we can use the empirical rule to describe the distribution of percentages.

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

8 0
3 years ago
ESP For several years, the General Social Survey asked subjects, “How often have you felt as though you were in touch with someo
belka [17]

The proportion who had<em> no such experience</em> was 0.362

<h3>
How the find the proportion?</h3>

Given:

Total sample: 3887

No that had no opinion: 1407

No that had at least one experience: 2480

Therefore, to find the proportion who had<em> no such experience</em> is:

Sample number/Total sample

1407/3887

=0.362

Read more about proportions here:

brainly.com/question/19994681

#SPJ1

8 0
2 years ago
I dont know how to do this, please help.
Anit [1.1K]

I'm assuming this is what they want? haha

5 0
3 years ago
Read 2 more answers
Other questions:
  • Words that were shakespeare's day but are not in use today are considered to be?
    6·1 answer
  • According to the world atlas (2010) the population of New York City was 19,750,000, the population of Los Angeles was 15,250,000
    11·1 answer
  • What is the answer to his question
    12·1 answer
  • How large a sample n would you need to estimate p with margin of error 0.04 with 95% confidence? Assume that you don’t know anyt
    10·1 answer
  • Factor over complex numbers 2x^4+36x^2+162
    11·1 answer
  • Write 863.141 in expanded form
    11·1 answer
  • What is the answer ​
    9·1 answer
  • Help please help me I need this
    15·1 answer
  • Help me solve them plsss...both of the questions :)
    12·2 answers
  • A trapezoid has a height of 10 centimeters. One parallel base has a length of 7 centimeters, and the other parallel base has a l
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!