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notsponge [240]
3 years ago
9

1. There are 324 fourth grade students at Lincoln Elementary School. There are 12 fourth grade classrooms. How many students wil

l be in each class?
Answers:
1.26 students
2.27 students
3.37 students
4.None of These is correct
Mathematics
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

2.27 students

Step-by-step explanation:

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A telephone company charges a fixed monthly rate plus a rate per minute of usage. The company charges $120 for 100 minutes of us
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The answer to this is C.
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Started business whit cash Rs 250000 and Machinery Rs 200000<br>Accounting equation ​
oksano4ka [1.4K]

\huge\purple{Answer}

In case there is no double entry system is followed, profit can be calculated by comparing the opening and closing capital. In the given situation this can be calculated as:

Opening Capital Rs.200000

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Less: Drawings Rs. 30000

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7 0
3 years ago
Read 2 more answers
Of a squirrel's hidden nuts, for every 5 that get found, there are 3 that do not get found. A squirrel hid 40 nuts all together.
koban [17]

Answer:

15 nuts do not get found.

Step-by-step explanation:

Given that Of a squirrel's hidden nuts, for every 5 that get found, there are 3 that do not get found.

Total number of nuts squirrel had hidden = 40

Proportion of nuts not found to total = 3/(3+5) = 3/8

Hence out of 40, nuts not found =3/8(40) = 15 nuts.

15 nuts would not be found and 25 nuts would be found if squirrel had hidden in total 40 nuts.

This is because the proportion of found:unfound = 5:3

Hence 25:!5 =5:3 satisfies this

15 nuts are not found.

5 0
3 years ago
Read 2 more answers
Petes boat can travel 48 miles upstream in 4 hours. The return trip takes 3 hours. Find the speed of the boat in still water and
tankabanditka [31]
So... hmm bear in mind, when the boat goes upstream, it goes against the stream, so, if the boat has speed rate of say "b", and the stream has a rate of "r", then the speed going up is b - r, the boat's rate minus the streams, because the stream is subtracting speed as it goes up

going downstream is a bit different, the stream speed is "added" to boat's
so the boat is really going faster, is going b + r

notice, the distance is the same, upstream as well as downstream
thus   \bf \begin{cases}&#10;b=\textit{rate of the boat}\\&#10;r=\textit{rate of the river}&#10;\end{cases}\qquad thus&#10;\\\\\\&#10;&#10;\begin{array}{lccclll}&#10;&distance&rate&time(hrs)\\&#10;&----&----&----\\&#10;upstream&48&b-r&4\\&#10;downstream&48&b+4&3&#10;\end{array}&#10;\\\\\\&#10;&#10;\begin{cases}&#10;48=(b-r)(4)\to 48=4b-4r\\\\&#10;\frac{48-4b}{-4}=r\\&#10;--------------\\&#10;48=(b+r)(3)\\&#10;-----------------------------\\\\&#10;thus\\\\&#10;48=\left[ b+\left(\boxed{\frac{48-4b}{-4}}\right) \right] (3)&#10;\end{cases}

solve for "r", to see what the stream's rate is

what about the boat's? well, just plug the value for "r" on either equation and solve for "b"
5 0
3 years ago
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