Answer:
3
+ 11a³ - 7a² + 18a - 18
Step-by-step explanation:
<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>
(a² + 4a - 6) × (3a² - a + 3) =
(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}
<u>Now we can evaluate the terms in the brackets. </u>
(a² × 3a²) + {a² × (-a)} + (a² × 3) + (4a × 3a²) + {4a × (-a)} + (4a × 3) + {(-6) × a²) + {(-6) × (-a)} + {(-6) × 3} =
3 + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18)
<u>We can open the brackets now. One plus and one minus makes a minus. </u>
3 + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =
3 -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18
<u>Evaluate like terms.</u>
3 -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3 + 11a³ - 7a² + 18a - 18
(2x+24)
(11b-33)
(8s-8)
(36+6y)
(25z-100)
(35w-70)
Answer:
Binomial; \mu p=87.5, \sigma p=7.542
Step-by-step explanation:
- a distribution is said be a binomial distribution iff
- The probability of success of that event( let it be p) is same for every trial
- each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
- there are fixed number of trials (n)
- the trials are independent
- here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)
- the probability of success(0.35) is same for every trial
(35/100=0.35 is the required p here)
[since, the formula for 
]
[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}
- therefore, it is Binomial; \mu p=87.5, \sigma p=7.542
X is the ounces
Got this answer because you figured it out
Y = kx where k is a constant
27 = k*9
k = 27/9 = 3
required variation is y = 3x
