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musickatia [10]
3 years ago
12

HI. Can you help???

Mathematics
1 answer:
Maslowich3 years ago
3 0

Answer:

The maximum rate of change is between second 15 and second 19.

Step-by-step explanation:

See the attached table.

The table shows the total distance a spider traveled after a light was turned on.

Now, the average rate of change between two consecutive times in the table is given by  

= \frac{\textrm {Total change in Distance in feet}}{\textrm {Total change in Time in seconds }}

Therefore, between second 5 and second 11, the average rate of change = \frac{7 - 4}{11 - 5} = 0.5

Between second 11 and second 15, the average rate of change = \frac{13 - 7}{15 - 11} = 1.5

Between second 15 and second 19, the average rate of change = \frac{20 - 13}{19 - 15} = 1.75

Between second 19 and second 28, the average rate of change = \frac{24 - 20}{28 - 19} = 0.44

Therefore, the maximum rate of change is between second 15 and second 19. (Answer)

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Solve the equation. Round to the nearest thousandth. -12e-x + 8 = 7​
Marysya12 [62]

Answer:

-12e-x + 8 = 7

-12e-x = 7-8

-12e-x = -1

12e-x = 1

e-x = 1/12

ln(e-x) = ln(1/12)

x = -ln(1/12)

x = -2.485

7 0
3 years ago
Select all possible values for x that solve the equation x^2=800
Gemiola [76]

x^2 = 800. Take the square root of each side.

x = √(800) and -√(800)

6 0
3 years ago
I need help with this please
Nookie1986 [14]

Answer:

steps below

Step-by-step explanation:

3.2.1   AD = DB* sin 2 = DB * sin θ   .. DE // AB   ∠2= θ  ... (1)

By laws of sines:  DB / sin ∠5 = x / sin ∠4    

∠4 = θ-α     ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α

DB = (x*sin ∠5)/sin (θ-α)

     = (x* sin (90°+α)) / sin (θ-α)

AD = DB*sinθ

     = (x* sin (90°+α))*sinθ / sin (θ-α)

     = x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α)    .... sin90°=1, cos90°=0

     = x* cosα* sinθ / sin (θ-α)

3.2.2 Please apply Laws of sines to calculate the length

7 0
2 years ago
Need help with this question asap!!
adoni [48]
Well. it's possible that the segments are congruent but the other answer aren't as probable.
6 0
3 years ago
A truck with a heavy load drove from Boston to New York at 50 mph. After dropping of the load, it returned from New York to Bost
leva [86]

Answer:

175/3 or 58.333...

Step-by-step explanation:

This is fairly complicated but I will try to make it as simple as possible. I also apologize in advance for how impossible it is to make fractions look like fractions. I also had to insert a bunch of unnecessary parentheses just because the fractions that I can make are relatively inaccurate.

The distance between 2 cities can be represented as d.

Time is d/r if r is rate, so B->NY=d/50

Similarly,NY->B is d/70

Obviously the average speed is 2d/(d/50+d/70), this is just an average time

Now just remove the d and get (d/d)*2/(1/50+1/70)

You can now multiply by the LCM/LCM, which is 350/350.

After calculating you will get 700/12 which is 58.333...(This is how to enter into your RSM browser) Hope this helps. Sorry it is so late.

8 0
3 years ago
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