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3 years ago

HI. Can you help???

Mathematics

1 answer:

Maslowich3 years ago

3 0

Answer:

The maximum rate of change is between second 15 and second 19.

Step-by-step explanation:

See the attached table.

The table shows the total distance a spider traveled after a light was turned on.

Now, the average rate of change between two consecutive times in the table is given by

= $\frac{\textrm {Total change in Distance in feet}}{\textrm {Total change in Time in seconds }}$

Therefore, between second 5 and second 11, the average rate of change = $\frac{7 - 4}{11 - 5} = 0.5$

Between second 11 and second 15, the average rate of change = $\frac{13 - 7}{15 - 11} = 1.5$

Between second 15 and second 19, the average rate of change = $\frac{20 - 13}{19 - 15} = 1.75$

Between second 19 and second 28, the average rate of change = $\frac{24 - 20}{28 - 19} = 0.44$

Therefore, the maximum rate of change is between second 15 and second 19. (Answer)

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Step-by-step explanation:

3x - 5y = 8

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3 years ago

A collector has 120 movie posters and 100 band posters. She wants

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Answer:

She should sell 20 band posters from total 80 to keep the maintain the same ratio.

Step-by-step explanation:

The total number of movie posters collector has = 120

The total number of band posters collector has = 80

The current ratio of movie poster : band poster = 120 : 100

or, reducing the ratio further, we get

ratio of movie poster : band poster = 6 : 5 ...... (1)

Now, the number of posters she wants to sell = 24

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Answer:

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