Part A is asking you to substitute x for 6 and solve. Part B asks you to substitute x for -4.
Answer:
Step-by-step explanation:
Answer: Lets divide by 8. My god, those coefficients are large.
x^3 - 8x^2 + 20x - 16 = 0
Possible integral roots are: +1, -1, +2, -2, +4, -4, +8, -8
If x = 2, f(x) = 8 - 32 + 40 - 16 = 0
Hence, x-2 is a factor.
Use synthetic division to get: x^2 - 6x + 8 = (x-4)(x-2).
Therefore, there are two integral roots: +2 and +4.
Step-by-step explanation:
Answer:
12/23/56
Step-by-step explanation:
