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frez [133]
3 years ago
5

Which expression is equivalent to 5^3?

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0

Answer:

C and D

Step-by-step explanation:

5^3 - 5^0 = 125 - 1 = 124, so it's not A

5^12 / 5^4 = 5^(12-4) = 5^8, so it's not B

5^7 * 5^-4 = 5^(7+(-4)) = 5^3, so it can be C

5^0 * 5^3 = 5^(0+3) = 5^3, so it can be D

5 + 5^2 = 5 + 25 = 30, so it can't be E

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Y = x + 3/1

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F(x) = - 2x<br> g(x) = 8x^2– 5x+7<br> Find (f .g)(x).
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Answer:

\large\boxed{(f\cdot g)(x)=-16x^3+10x^2-14x}

Step-by-step explanation:

f(x)=-2x\\\\g(x)=8x^2-5x+7\\\\(f\cdot g)(x)=f(x)\cdot g(x)\\\\\text{substitute:}\\\\(f\cdot g)(x)=(-2x)(8x^2-5x+7)\qquad\text{use the distributive property}\\\\(f\cdot g)(x)=(-2x)(8x^2)+(-2x)(-5x)+(-2x)(7)\\\\(f\cdot g)(x)=-16x^3+10x^2-14x

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People with restless leg syndrome have a strong urge to move their legs to stop uncomfortable sensations. People with fibromyalg
USPshnik [31]

Answer:

0.1833

Step-by-step explanation:

Given:

% of people with fibromyalgia = 2%

Probability of having a restless leg syndrome for people with fibromyalgia = 0.33

Probability of having a restless leg syndrome for people without fibromyalgia = 0.03

Take F as event of having fibromyalgia

Take R as event of having restless leg

Required:

Find the probability that a person with restless leg syndrome has fibromyalgia.

To find the probability that a person with restless leg syndrome has fibromyalgia, we have: P(F/R)

P(F/R) = \frac{P(F n R)}{P(R)}

P(F/R) =\frac{P(R/F) * P(F)}{P(R/F) * P(F) + P(R/F^c) * P(F^c)}

Where,

P(R/F) = 0.33

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P(R/F') = 0.03

P(F') = 1 - 0.02 = 0.98

Therefore,

P(F/R) = \frac{0.33 * 0.02}{0.33*0.02 + 0.03*0.98}

= 0.1833

Probability a person with restless leg syndrome has fibromyalgia = 0.1833

Tree diagram is attached

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3 years ago
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