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AleksandrR [38]
3 years ago
13

Evaluate the following -5+(63/9)​

Mathematics
2 answers:
Softa [21]3 years ago
7 0

Answer: 36

Step-by-step explanation:

1

Order of operations dictates that the exponent be evaluated first, then the subtraction within the parenthesis, then the division within the brackets, then the multiplication.

RESULT                        36

alexandr402 [8]3 years ago
6 0

Evaluate parenthenses: -5+(63/9)=-5+7

-5+7 is 2

Hope this helped!

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Also may i have help with this one
mote1985 [20]
The answer should be 11 since adding all the x’s up before 13 equals 11
4 0
2 years ago
Usama needs to read 6 novels each month.
Delicious77 [7]

Answer:

78 novels

Step-by-step explanation:

N= novels

M= month

6N = 1M

? = 13M

6N × 13M= 78NM

78NM ÷ 1M

cancel M, therefore;

the number of novels Usama needs to read in 13 months is 78.

5 0
3 years ago
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These are the values in Greta’s data set. (2, 43), (3, 46), (4,61), (6, 70), (7,74) Greta determined the equation of a linear re
Dmitry_Shevchenko [17]
Okay, i'm pretty sure that if you make a residual plot its a plot using all those points labeled. So plot those points on a graph, if you are using a K12 diagram use the 1-10 as 100-1000 (basically add a zero to every number) 

4 0
3 years ago
Read 2 more answers
It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i
Salsk061 [2.6K]

Answer:

(-\infty, 0.2661)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

n=60 represent the sample size  

X=12 represent the number of masks that had lenses pop out at 250°

\hat p =\frac{12}{60}=0.2 represent the estimated proportion of masks that  had lenses pop out at 250°

p represent the population proportion of masks that  had lenses pop out at 250°

Confidence =0.9 or 90%

\alpha=0.1 represent the significance level

Confidence interval

On this case we want a interval on this form : (-\infty,\hat p +z_{\alpha}\sqrt{\frac{\hat p (1-\hat p)}{n}})

So the critical value would be on this case z_{\alpha}=1.28 and we can use the following excel code to find it: "=NORM.INV(1-0.1,0,1)"

We found the lower limit like this:

0.2 +1.28\sqrt{\frac{0.2 (1-0.2)}{60}}=0.2661

And the interval would be: (-\infyt, 0.2661)

3 0
4 years ago
Help me please!!! i need this!!
Nadya [2.5K]

Answer:

c

Step-by-step explanation:

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3 years ago
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