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3 years ago

Which exponential equation is equivalent to the logarithmic equation below?log 784 = a

Mathematics

2 answers:

spin [16.1K]3 years ago

7 0

Answer:

Apex the answer is 10^a=784

Step-by-step explanation:

Alexeev081 [22]3 years ago

6 0

The general form of logarithmic function is $log_{b}$ y = x
We can transform it to exponential function by following the general form of exponential function y = $b^{x}$

we have:

b = 10 ⇒ if the base of logarithm is not given, its default value is 10
x = a
y = 784

our exponential form in this is

784 = $10^{a}$

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What fraction has a decimal value between 1/2 and 3/4

andreyandreev [35.5K]

To find the decimal value, we must convert 1/2 and 3/4 into decimal.
1/2=0.5
3/4=0.75
Now we just have choose a random decimal in between the decimal.
Let's choose 0.6
Now we have to convert the decimal into a fraction. So we'll multiply the decimal by100.
0.6×100=60
Then we make the 60 into a fractions. 60/100
Then we'll simply the fraction. 60/100÷10=6/10÷2=3/5
There you go. You have your answer.

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3 years ago

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Wewaii [24]

The answer is A. x-6=18 and x+6=18.

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3 years ago

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1.12cm=______mm 2.124mm=_______cm 3.2cm=________mm 4.7mm=_______cm

sashaice [31]

Answer:

1. 11.2 mm

2. 0.2124cm

3. 32mm

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3 years ago

Solve by unfolding: a0=2, and, n>=1, a_n=7a_n-1.

vodomira [7]

We are told that the first term is 2. The next term is 7(2) = 14; the third term is 7(14) = 98. And so on. So, the first term and the common ratio (7) are known.

The nth term of this geometric series is a_n = 2(7)^(n-1).

Check: What is the first term? We expect it is 2. 2(7)^(1-1) = 2(1) = 2. Correct.

What is the third term? We expect it is 98. 2(7)^(3-1) = 2(7)^2 = 98. Right.

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3 years ago

It takes 24 megabytes to store 144 songs on a music player. What is the greatest number of songs that 60 megabytes could store?

givi [52]

Option B

We can store a total of 360 songs in 60 megabytes of space.

Solution:

It is given to us that It takes 24 megabytes to store 144 songs on a music player. We have been asked to find out what is the greatest number of songs that 60 megabytes could store.

To solve this question we can use the unitary method.

We will first find out how many songs can be stored in 1 megabyte. This can be done as follows:

$=\frac{144}{24}=6$

Therefore, we can store 6 songs in 1 megabyte.

So, in 60 megabyte we can store the following number of songs:

$=60 \times 6=360$

So, we can store a total of 360 songs in 60 megabytes.

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3 years ago