<h2>
![16 - 3(8 - 3) {}^{2} \div 5](https://tex.z-dn.net/?f=16%20-%203%288%20-%203%29%20%7B%7D%5E%7B2%7D%20%20%5Cdiv%205)
</h2><h2>ANSWER</h2>
<h2>
![1](https://tex.z-dn.net/?f=1)
</h2><h3>EXPLANATION</h3>
![16 - 3 \times 5 {}^{2} \div 5](https://tex.z-dn.net/?f=16%20-%203%20%5Ctimes%205%20%7B%7D%5E%7B2%7D%20%20%5Cdiv%205)
![16 - 3 \times 5 {}^{2} \div 5 {}^{1}](https://tex.z-dn.net/?f=16%20-%203%20%5Ctimes%205%20%7B%7D%5E%7B2%7D%20%20%5Cdiv%205%20%7B%7D%5E%7B1%7D%20)
![16 - 3 \times 5 {}^{2} \div 5 {}^{ - 1}](https://tex.z-dn.net/?f=16%20-%203%20%5Ctimes%205%20%7B%7D%5E%7B2%7D%20%20%5Cdiv%205%20%7B%7D%5E%7B%20-%201%7D%20)
![16 - 3 \times 5 {}^{2 - 1}](https://tex.z-dn.net/?f=16%20-%203%20%5Ctimes%205%20%7B%7D%5E%7B2%20-%201%7D%20)
![16 - 3 \times 5 {}^{1}](https://tex.z-dn.net/?f=16%20-%203%20%5Ctimes%205%20%7B%7D%5E%7B1%7D%20)
![16 - 3 \times 5](https://tex.z-dn.net/?f=16%20-%203%20%5Ctimes%205)
![16 - 15](https://tex.z-dn.net/?f=16%20-%2015)
![1](https://tex.z-dn.net/?f=1)
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Answer: D) Not possible
SSA is not a valid congruence theorem. Note how the angles are not between the congruent sides.
Answer:
The answer is s = 1.
Step-by-step explanation:
Opposite sides of a parallelogram are equal so,
3s + 19 = s + 21
3s - s = 21 - 19
2s = 2
s = 1
next,
s + 21 =? 3s + 19
1 + 21 equal to (?) 3(1) + 19
22 = 22
so the answer is correct
<span><span>y=−<span>x2</span>+2x−7</span><span>y=-<span>x2</span>+2x-7</span></span>Complete the square on the right side of the equation.Tap for more steps...<span><span>−<span><span>(x−1)</span>2</span>−6</span><span>-<span><span>(x-1)</span>2</span>-6</span></span>Reorder the right side of the equation to match the vertex form of a parabola.<span><span>y=−<span><span>(x−1)</span>2</span>−6</span><span>y=-<span><span>(x-1)</span>2</span>-6</span></span>Use the vertex form, <span><span>y=a<span><span>(x−h)</span>2</span>+k</span><span>y=a<span><span>(x-h)</span>2</span>+k</span></span>, to determine the values of <span>aa</span>, <span>hh</span>, and <span>kk</span>.<span><span>a=−1</span><span>a=-1</span></span><span><span>h=1</span><span>h=1</span></span><span><span>k=−6</span><span>k=-6</span></span>Find the vertex <span><span>(h,k)</span><span>(h,k)</span></span>.<span><span>(1,−6)</span><span>(1,-6)</span></span>