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Leto [7]
4 years ago
12

HELLLLLP ill make you brainiest and ill give u a lot of points if you HELP ME Directions Part One.

Computers and Technology
2 answers:
Vesnalui [34]4 years ago
6 0
The revised email is shown below: 
E-mail A: Good Day! Is it possible that I will be receiving the training manual this morning because I will be needing it for my next shift. 
E-mail B: A customer has a concern regarding the bill that she paid. In the end, she realized that it was a mistake on her part and she wants to call again tomorrow. 

Leni [432]4 years ago
4 0
I think it would be email a
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a password to a certain database consists of digits that cannot be repeated. if the password is known to consist of at least 8 d
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\frac{10!}{2}mins

Explanation:

12 seconds to try one combination will be equivalent to  \frac{1}{12}\times 60 = \frac{1}{5} \ mins

Password contain at least 8 digit i.e. password can contain 8, 9, 10 digit.

Password cannot contain more than 10 digit because it will give room for repetition which it is clearly stated that digit cannot be repeated.

Possible digit that can be used: 9,8,7,6,5,4,3,2,1,0.

Total number of passwords combination possible for each position in 8 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3. Total number of passwords combination possible in 8 digit is equivalent to \frac{10!}{2}.

Total number of passwords combination possible for each position in 9 digit.  

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2. Total number of passwords combination possible in 9 digit is equivalent to \frac{10!}{1}.

Total number of passwords combination possible for each position in 10 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2, 10th position = 1.  Total number of passwords combination possible in 10 digit is equivalent to 10!.

Adding them up and multiplying by  \frac{1}{5} \ mins  to get the total number of time needed to guarantee access to database =  [\frac{10!}{2}\times\ \frac{10!}{1} \times 10!] \frac{1}{5}\ mins = \frac{10!}{2}

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