Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
Multiply the equation:
The solution set is the same, because multiplying both sides of an equation by a non-zero number doesn't change the solution set. In fact, if you rewrite the equation as
Multiplying this by 3 (or whatever number, for all it matters) gives
Now, a product is zero if and only if at least one of the factor is zero. So, either 
or
Since the first is clearly impossible, the second one must be true, which is the original equation.
Answer:
Percent of rise of a new truck on a used truck = 15%
Step-by-step explanation:
Let x be the percentage of saved money if Jason buying a used truck.
Given:
Price of the used truck = $34,000
Price of the new truck = $40,000
We need to find the percent of rise Jason saves on a used truck rather than buying a new truck
Solution:
Using a percentage formula.
Substitute Percentage cost = 34,000 and Original cost = 40,000 in above formula.
(
)
Using cross multiplication rule.
x = 15%
Therefore, Jason used 15% rise of a new truck for a used truck.
Answer:
Step-by-step explanation:
The angle at E is 90 degrees.
All tangents of a circle always meet the radius at a 90 degree angle.
90 + 67 + G = 180o All triangles have 180 degrees. Combine left.
157 + G = 180o Subtract 157 from both sides.
157 - 157 + G + 180 - 157
G = 23
The <em><u>correct answers</u></em> are:
Angle A is congruent to angle E; and BC=FD.
Explanation:
For ASA, we want two angles and an included side of one triangle congruent to two angles and an included side of the other triangle. The sides we have marked are AC and DE; the angles already marked congruent are C and D. In order to be ASA, the other angle must be on the other side of the congruent side; this means that we have angles A and E.
For SAS, we want two sides and an included angle of one triangle congruent to two sides and an included angle of the other triangle. We have angles C and D congruent and sides AC and DE congruent. In order to be SAS, the other side must be on the other side of the congruent angle; this means we have sides BC and FD.
