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seropon [69]
3 years ago
11

20 POINTS! Please help

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
Hey! I believe the answer is A. Have a nice/great day! :-)
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When calculating accrued interest over several years that compounds annually, you must _____.
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When calculating accrued interest over several years that compounds annually, you must calculate a new principle each year, adding the accrued interest from the previous year. At the beginning of the new interest period, all the accrued interest is added to the principal which forms a new principle figure that the interest is then counted on. 
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Which numbers are divisible by 9? 119 702 432 641 372
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702 divided by 9 is 78
432 divied by 9 is 48
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*Find the formula of the series 1+2²+3²+4²+....+n²*<br>​
Sophie [7]

The formula is \frac{n(n+1)(2n+1)}{6}

What are series?

In mathematics, we can describe a series as adding infinitely many numbers or quantities to a given starting number or amount.

We will find the formula as shown as below:

Let S=1+2^2+3^2+4^2+................+n^2

We know (n+1)^3=n^3+3n^2+3n+1

(1+1)^3=1^3+3(1)^2+3(1)+1

(2+1)^3=2^3+3(2)^2+3(2)+1

(3+1)^3=3^3+3(3)^2+3(3)+1

.

.

(n+1)^3=n^3+3(n)^2+3(n)+1

On adding

2^3+3^3+4^3......(n+1)^3=(1^3+2^3+3^3+.....+n^3)+3(1^2+2^2+.....+n^2)+3(1+2+3....n)+(1+1+1+....+1)

2^3+3^3+4^3......(n+1)^3-(1^3+2^3+3^3+.....+n^3)=3S+\frac{3n(n+1)}{2}+(1+1+1+....+1)

(n+1)^3-1^3=3S+\frac{3n(n+1)}{2} +n

n^3+3(n)^2+3(n)+1-1=3S+\frac{3n(n+1)}{2} +n

2n^3+6n^2+6n=6S+3n^2+3n+2n

6S=2n^3+3n^2+n

6S=2n^2(n+1)+n(n+1)

6S=(n+1)(2n^2+n)

6S=n(n+1)(2n+1)

S=\frac{n(n+1)(2n+1)}{6}

Hence, the formula is \frac{n(n+1)(2n+1)}{6}

Learn more about Series here:

brainly.com/question/24643676

#SPJ1

3 0
2 years ago
With a tail wind, a small aircraft can fly 1200
Irina-Kira [14]

Answer:

total distance= 12000+12000=24000

total time = 5+6=11

average speed of plane= 24000/11

3 0
2 years ago
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