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3 years ago

14

The volume of a cylinder is 647 cubic centimeters. If the radius of the cylinder is 4 cm, what is the height of the cylinder? (V

= Tr+h)

1 answer:

Amiraneli [1.4K]3 years ago

4 0

Answer:

The height h = 12.87 cm.

Step-by-step explanation:

Volume = pi r^2 h

647 = pi 4^2 h

h = 647 / 16pi

h = 12.87 cm.

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1. Which expression is equivalent to 5(10+a)

Lostsunrise [7]

Answer:

50 + 5a

Step-by-step explanation:

<em>The expression is basically asking 'what is 5 times this quantity' so you multiply everything in that quantity by 5 aka Distribute the 5.</em>

5(10 + a)

50 + 5a

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3 years ago

Max points i need this for finals

sladkih [1.3K]

Answer:

$Slope (m) = \frac{y}{x} = \frac{3}{1} =3$

Step-by-step explanation:

$Slope (m) = \frac{y}{x} = \frac{3}{1} =3$

$0 = arctan(\frac{y}{x}) + 180^o = 251.56505117708^o$

X = -4 – -2 = -2

Y = 4 – 10 = -6

$Distance (d) = \sqrt{x^2+y^2}=\sqrt{40} = 6.3245553203368$

Equation of the line:

y = 3x + 16

When x=0, y = 16

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5 0

2 years ago

What is the lcm of 45 and 59

Grace [21]

Answer:

The answer is 2655.

Step-by-step explanation:

Basically all you have to do is lost some multiples for each number.

45: 45, 90, 135, 180, 225, 270, 315, 360, 405, 450, 495, 540, 585, 630, 675, 720, 765, 810, 855, 900, 945, 990, 1035, 1080, 1125, 1170, 1215, 1260, 1305, 1350, 1395, 1440, 1485, 1530, 1575, 1620, 1665, 1710, 1755, 1800, 1845, 1890, 1935, 1980, 2025, 2070, 2115, 2160, 2205, 2250, 2295, 2340, 2385, 2430, 2475, 2520, 2565, 2610, 2655

59: 59, 118, 177, 236, 295, 354, 413, 472, 531, 590, 649, 708, 767, 826, 885, 944, 1003, 1062, 1121, 1180, 1239, 1298, 1357, 1416, 1475, 1534, 1593, 1652, 1711, 1770, 1829, 1888, 1947, 2006, 2065, 2124, 2183, 2242, 2301, 2360, 2419, 2478, 2537, 2596, 2655

As you can see, 2655 is the first multiple they have in common.

So the lcm is 2655.

8 0

3 years ago

HELP ME!!!!!!!!!!!!!!!!!!!!!!

HACTEHA [7]

Answer:

A

Step-by-step explanation:

Multiply 120 by 5/8

5 0

3 years ago

How many ways can 2 Geometry books, 8 Algebra books and 2 Pre-Calculus books be arranged on a shelf if all the books of each res

mariarad [96]

Answer: 2,970

Step-by-step explanation:

The number of ways to arrange n things such that a things are identical , b things are identical , and so on is $\dfrac{n!}{a!\cdot b!\cdot ....}$ .

As per given , we have

Number of Geometry books = 2

Number of Algebra books = 8

Number of Pre-Calculus books =2

Total books = 2+8+2=12

Then, the number of ways to arrange them : $\dfrac{12!}{2!\cdot 8!\cdot 2!}$

$=\dfrac{12\times11\times10\times9\times8!}{2\times8!\times2}=2970$

Hence, the total number of ways to arrange 2 Geometry books, 8 Algebra books and 2 Pre-Calculus books is 2,970.

3 0

3 years ago