Question

PLEASE HELP!!!

Answer 1

Answer: B. About 93%

You have the correct answer.

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Explanation:

Focus solely on the "in anime club" row. We do this because of the phrasing "given the student is in the anime club". We know for a fact that whoever is randomly picked, they are in the anime club. So we don't have to worry about other data values in the other rows.

Divide the value 0.13 which is in the "takes Japanese" column over 0.14, which is in the "total" column.

Basically we're computing $P(A|B) = \frac{P(A \cap B)}{P(B)}$ where A and B represent the events "takes Japanese" and "in anime club" respectively. The upside down U symbol represents intersection to indicate both events are happening at the same time.

So we end up with 0.13/0.14 = 0.92857142857142 which rounds to 0.93, then that converts to 93% when you move the decimal point over to the right two spots.