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MAXImum [283]
3 years ago
9

Value 1: 45.58g

Chemistry
1 answer:
Rama09 [41]3 years ago
7 0

Answer:

<h2>Percentage error is a measurement of the discrepancy between an observed and a true, or accepted value .</h2>

Explanation:

<h3 />
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GarryVolchara [31]
It is the gravitational force pulling on something
4 0
4 years ago
help plz Which list is in order from smaller to larger sediment particles? A. sand, silt, clay B. clay, silt, sand C. silt, sand
MariettaO [177]

Answer : The correct option is B (clay, slit, sand).

Explanation :

Soil particles are of three types : Sand, Slit and clay. Most of the soils particles are made up of a combination of sand, slit and clay.

Particle size range of the sand = 2.00 -0.05 mm

Particle size range of the slit = 0.05 -0.002 mm

Particle size range of the sand = less than 0.002 mm

Sand is the largest soil particle, clay is the smallest soil particle and slit particle is present in between the sand & clay particle.

Therefore, the order from smaller to larger sediment particles is

Clay > Slit > Sand

5 0
4 years ago
What is a good description of potential energy? (1 point)
Brilliant_brown [7]

Answer:

I think the answer is stored energy

Explanation:

8 0
4 years ago
How many milliliters of an aqueous solution of 0.157 M magnesium nitrate is needed to obtain 17.4 grams of the salt?
Art [367]

Answer:

747mL of the 0.157mL are needed

Explanation:

To find the grams of salt we need to convert these grams to moles using molar mass of magnesium nitrate (148.3g/mol). Then, with the molar concentration we can convert the moles to liters and, as last, to milliliters, as follows:

<em>Moles Mg(NO₃)₂:</em>

17.4g * (1mol / 148.3g) = 0.117 moles of magnesium nitrate

<em>Volume:</em>

0.117 moles * (1L / 0.157moles) = 0.747L

= 747mL of the 0.157mL are needed

<em>In a 0.157M solution there are 0.157 moles per liter of solution</em>

8 0
3 years ago
If the mole fraction of nitric acid (HNO3) in an aqueous solution is 0.275, what is the percent by mass of HNO3?
jeka94
Molar mass of    N    = 14 g/molMolar mass of   O2    = 32 g/molAdding both masses = 46 g/molActual molar mass/ Empirical molar mass = 138.02 / 46 = 3Now multiplying this co effecient with empirical fomula NO2 = 3(NO2)                                                                                             = N3O6So according to above explanation,D) N3O6, is the correct answer.

8 0
3 years ago
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