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3 years ago

Value 1: 45.58g

Chemistry

1 answer:

Rama09 [41]3 years ago

7 0

Answer:

<h2>Percentage error is a measurement of the discrepancy between an observed and a true, or accepted value .</h2>

Explanation:

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Where does the LED Light get its energy directly from?

scZoUnD [109]

Answer:

A Light Emitting Diode (LED) is a solid-state semiconductor device that converts electrical energy directly into light. On its most basic level, the semiconductor is comprised of two regions.

Explanation:

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3 years ago

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g The following reaction is the first step in the production of nitric acid from ammonia. 4NH3(g) 5O2(g) → 4NO(g) 6H2O(g) Calcul

STatiana [176]

<u>Answer:</u> The enthalpy of the reaction is coming out to be -902 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]$

For the given chemical reaction:

$4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(4\times \Delta H_f_{(NO(g))})+(6\times \Delta H_f_{(H_2O(g))})]-[(4\times \Delta H_f_{(NH_3(g))})+(5\times \Delta H_f_{(O_2)})]$

We are given:

$\Delta H_f_{(NO(g))}=91.3kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H_f_{(NH_3(g))}=-45.9kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(4\times (91.3))+(6\times (-241.8))]-[(4\times (-45.9))+(5\times (0))]\\\\\Delta H_{rxn}=-902kJ$

Hence, the enthalpy of the reaction is coming out to be -902 kJ.

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4 years ago

“Na2SO3” represents sodium sulfite.What does the 4 mean in the formula 4Na2SO3?

Strike441 [17]

The mass of substance which consists the equal number of particles as 12 grams of Carbon-12 is said to be mole.

For example:

The balanced chemical equation for production of water from hydrogen and oxygen is:

$2H_2(g) + O_2(g) \rightarrow 2H_2O(l)$

That means 2 moles of $H_2$ reacts with 1 mole of $O_2$ to give 2 moles of $H_2O$ .

The given formula is $4Na_2SO_3$ .

Hence, 4 represents the number of moles in $4Na_2SO_3$ formula that is 4 moles of $Na_2SO_3$ .

The number of atoms of sodium, $Na$ in $4Na_2SO_3$ is:

$4 \times 2 = 8$

The number of atoms of sulfur, $S$ in $4Na_2SO_3$ is:

$4 \times 1 = 4$

The number of atoms of oxygen in, $O$ in $4Na_2SO_3$ is:

$4 \times 3 = 12$

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3 years ago

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What is an example of a community protecting Earth's resources? (2 points)

Lerok [7]

D. A town has started a new recycling and composting program

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3 years ago

2. A sample of helium gas has a volume of 200.0 mL at 0.960 atm. What pressure, in atmospheres, is needed to reduce the volume a

brilliants [131]

Answer:

3.840 atm

Explanation:

We use Boyle's law, which relates the pressure (P) and the volume (V) of a gas at a constant temperature. The change from initial P and V (P₁ and V₁) to final P and V (P₂ and V₂) is expressed as:

P₁V₁ = P₂V₂

We have the following data:

P₁= 0.960 atm

V₁= 200.0 mL

V₂ = 50.0 mL

Thus, we introduce the data in the equation and calculate the final pressure P₂:

P₂ = P₁V₁/V₂= (0.960 atm x 200.0 mL)/50.0 mL = 3.840 atm

Therefore, a pressure of 3.840 atm is needed to reduce the volume of the gas from 200.0 mL to 50.0 mL.

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3 years ago