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4 years ago

How is electrical energy used?

Chemistry

2 answers:

lana66690 [7]4 years ago

6 0

In heating, lighting, washing, watering, entertainment, and cooking.

Lesechka [4]4 years ago

4 0

We use electric energy in most everything in our house such as entertainment, heating, lighting, refrigeration, cooking, washing, and drying! Hope this helped! :)

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For IR radiation with û = 1,130 cm 1, v=__THz

Dmitry [639]

Answer: The frequency of the radiation is 33.9 THz

Explanation:

We are given:

Wave number of the radiation, $\bar{\nu}=1130cm^{-1}$

Wave number is defined as the number of wavelengths per unit length.

Mathematically,

$\bar{\nu}=\frac{1}{\lambda}$

where,

$\bar{\nu}$ = wave number = $1130cm^{-1}$

$\lambda$ = wavelength of the radiation = ?

Putting values in above equation, we get:

$1130cm^{-1}=\farc{1}{\lambda}\\\\\lambda=\frac{1}{1130cm^{-1}}=8.850\times 10^{-4}cm$

Converting this into meters, we use the conversion factor:

1 m = 100 cm

So, $8.850\times 10^{-4}cm=8.850\times 10^{-4}\times 10^{-2}=8.850\times 10^{-6}m$

The relation between frequency and wavelength is given as:

$\nu=\frac{c}{\lambda}$

where,

c = the speed of light = $3\times 10^8m/s$

$\nu$ = frequency of the radiation = ?

Putting values in above equation, we get:

$\nu=\frac{3\times 10^8m/s}{8.850\times 10^{-4}m}$

$\nu=0.339\times 10^{14}Hz$

Converting this into tera Hertz, we use the conversion factor:

$1THz=1\times 10^{12}Hz$

So, $0.339\times 10^{14}Hz\times \frac{1THz}{1\times 10^{12}Hz}=33.9THz$

Hence, the frequency of the radiation is 33.9 THz

7 0

3 years ago

Which of the following best describes an object that is accelerating? *

Flauer [41]

Answer:

a soccer ball travels at 3m/s

7 0

3 years ago

If 18 mL of methanol is used to make an aqueous solution that is 15% methanol by volume, how many mL of solution is produced?

Yuri [45]

Answer:

120.0 mL.

Explanation:

As it is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.

We suppose that the initial W% of methanol is 100.0 %

∴ (W%V) before dilution = (W%V) after dilution.

W% before dilution = 100.0 %, V before dilution = 18.0 mL.

W% after dilution = 15.0 %, V after dilution = ??? mL.

∴ V after dilution = (W%V) before dilution/W% after dilution = (100.0 %)(18.0 mL)/(15.0%) = 120.0 mL.

7 0

3 years ago

CAN SOMEONE HELP ME WITH THIS

cupoosta [38]

Answer: it is one parent

and a

Explanation:

5 0

3 years ago

uppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read

victus00 [196]

Answer:

20.25 mL.

Explanation:

The volume of base required for the titration can be derived by removing the base titrant volume from the volume at endpoint.

i.e Final volume - initial volume

= (22.08 - 1.83)mL

= 20.25 mL.

(Repeat and average volume results for accuracy.)

5 0

4 years ago