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lana66690 [7]
3 years ago
7

How to use bernoulli's equation.

Physics
1 answer:
saveliy_v [14]3 years ago
5 0

Answer:

Answer is below ….

Explanation:

The Bernoulli equation is a crucial statement that connects a fluid's pressure, height, and velocity at a single point in its flow. In an idealised system, the connection between these fluid conditions along a streamline always equals the same constant along that streamline.

Water from a reservoir runs through enormous tubes called penstocks before reaching a turbine at the end of a hydroelectric dam. The gravitational potential energy drops as the water flows down the pipe according to Bernoulli's equation, yet in many configurations, the water departs at the same speed.

Bernoulli's equation is a more broad and mathematical version of Bernoulli's principle that includes variations in gravitational potential energy. We'll derive this equation in the following part, but first, let's look at Bernoulli's equation to get a sense of what it says and how one may use it.

________________________________________________________

(hope this helps can I pls have brainlist (crown)☺️)

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5. A cable is attached 32.0 m from the base of a flagpole that is about to
soldi70 [24.7K]

Answer:

The length of the flagpole is approximately 87.43 m

Explanation:

The given parameters of the cable attached to the flagpole are;

The point along the flagpole at which the cable is attached = 32.0 m

The angle with respect to the ground at which the raising of the flagpole is halted = 60.0°

The downward force exerted by the cable, F_v = 1.233 × 10⁴ N

The force exerted by the cable to the left = 1.233 × 10⁴ N

Let 'W' represent the weight of the flagpole, at equilibrium, we have;

The sum of vertical forces = 0

Therefore;

F_v + W - R = 0

W - R = -1.233 × 10⁴ N

Taking moment about the support at the base of the pole, we get;

1.233 × 10⁴ × d × cos(60.0°) - 1.233 × 10⁴ ×d× sin(60.0°) + W × d/2 ×cos(60.0°) = 0

∴ W × d/2 ×cos(60.0°) ≈  4513.093·d  

W = 2 × 4513.093/(cos(60.0°)) ≈ 18,052.373 N

R = 18,052.373 + 1.233 × 10⁴ ≈ 30,382.373

R ≈ 30,382.373 N

Taking moment about the point of attachment of the cable to the ground, we have;

W × ((d/2) × cos(60.0°) + 32) = R × 32

∴ (d/2) = ((30,382.373 × 32/18,052.373) - 32)/(cos(60.0°)) ≈ 43.71281

d = 2 × 43.71281 ≈ 87.43

The length of the flagpole, d ≈ 87.43 m

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<span>♡♡Hope I helped!!! :)♡♡
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