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kirill115 [55]
3 years ago
5

A 60 kg runner accelerates during a race at 3m/s2. what force is exerted on the earth with each step

Physics
1 answer:
marusya05 [52]3 years ago
6 0

Answer:

180 Newton(N)

Explanation:

force =mass *acceleration

=60 * 3

=180 kgm/s^2

=180 N

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What would happen to a moving object if no unbalanced force acts upon it?<br> Help please?
Kisachek [45]

Answer:

B

Explanation:

if no force acts upon it it will just continue moving

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A-10A twin-jet close-support airplane is approximately rectangular with a wingspan (the length perpendicular to the flow directi
Sidana [21]

Solution :

Given :

Rectangular wingspan

Length,L = 17.5 m

Chord, c = 3 m

Free stream velocity of flow, $V_{\infty}$ = 200 m/s

Given that the flow is laminar.

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      $=\frac{1.225 \times 200 \times 3}{1.789 \times 10^{-5}}$

    $= 4.10 \times 10^7$

So boundary layer thickness,

$\delta_{L} = \frac{5.2 L}{\sqrt{Re_L}}$

$\delta_{L} = \frac{5.2 \times 3}{\sqrt{4.1 \times 10^7}}$

    = 0.0024 m

The dynamic pressure, $q_{\infty} =\frac{1}{2} \rho V^2_{\infty}$

                                           $ =\frac{1}{2} \times 1.225  \times 200^2$

                                          $=2.45 \times 10^4 \ N/m^2$

The skin friction drag co-efficient is given by

$C_f = \frac{1.328}{\sqrt{Re_L}}$

     $=\frac{1.328}{\sqrt{4.1 \times 10^7}}$

     = 0.00021

$D_{skinfriction} = \frac{1}{2} \rho V^2_{\infty}S C_f$

                  $=\frac{1}{2} \times 1.225 \times 200^2 \times 17.5 \times 3 \times 0.00021$

                  = 270 N

Therefore the net drag = 270 x 2

                                      = 540 N

7 0
2 years ago
What is the mode of 3, 9, 11, 11, 3, 6, 2, 2, 11?<br> 0<br> 11<br> 2<br> 5,5
hodyreva [135]

Answer:11

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5 0
3 years ago
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A speed versus time graph is shown:
erma4kov [3.2K]

In the given graph, from 4.0 s to 8.0 s, the object is at rest because the speed is zero.

In the given graph we can deduce the following;

  • at the time interval, 0 s to 3.5 s, the speed of the object = 1 cm/s
  • when the time, t= 4 s, the <em>speed</em> of the object = 0 cm/s
  • at the time interval, 4.0 s to 8.0 s, the<em> speed </em>of the object = 0 cm/s

When the <em>speed</em> of an object is zero (0), the object is simply at rest.

Thus, we can conclude that in the given graph, from 4.0 s to 8.0 s, the object is at rest because the speed is zero.

Learn more here:brainly.com/question/10454047

6 0
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