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3 years ago

5 ejemplos de ondas mecánicas PORFAVOR!!

1 answer:

6 0

Answer: Una onda de sonido es un ejemplo de onda mecánica. Las ondas sonoras son incapaces de viajar a través del vacío. Las ondas furtivas, las ondas del agua, las ondas de los estadios y las ondas para saltar la cuerda son otros ejemplos de ondas mecánicas; cada uno requiere algún medio para existir.

English Translation: A sound wave is an example of a mechanical wave. Sound waves are incapable of traveling through a vacuum. Slinky waves, water waves, stadium waves, and jump rope waves are other examples of mechanical waves; each requires some medium in order to exist.

Explanation:

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Which part of a sandwich is most like a homogeneous mixture?

hoa [83]

Bread is considered to be a heterogeneous mixture. It is a heterogeneous mixture because all of the components that are used to make the bread are physically separate.

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4 years ago

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Which of the following is contained in a pull start lawnmower?

Ksivusya [100]

A wheel and axle and an inclined plane.

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3 years ago

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If something is 50% efficient, how many joules of wasted energy will there be if 750J of energy is put in?

evablogger [386]

Answer:

375J of wasted energy

Explanation:

Efficiency=work output/work input×100%

50=w.o/750×100

750×50=100w.o

w.o=750×50/100

w.o=75×5

w.o=375J

Wasted energy=750J-375J

=375J

Aliter

If the machine is 50% efficient then it is also 50% inefficient

50%×750J=375J

5 0

3 years ago

Two point charges, q1 = 2.0 × 10−7 C and q2 = −6.0 × 10−8 C, are held 25.0 cm apart. (a) What is the electric field at a point 5

AlladinOne [14]

Answer:

a) $432000\frac{N}{C}\hat{i}$

b) $-6.92\times10^{-14}N\hat{i}$

Explanation:

The magnitude of the electric field generated by a charged particle at a distance r is:

$E= k\frac{|Q|}{r^{2}}$

With Q the charge of the particle and k the constant ()

So, the electric field generated by q1 knowing that the point 5.0 cm apart the negative charge is $25.0cm-5.0cm=20.0 cm=0.2m$ apart the positive charge is:

$E_1= k\frac{|q1|}{r_1^{2}} =(9.0\times10^{9}\,\frac{Nm^{2}}{C^{2}})\frac{|2.0\times10^{-7}|}{(0.2)^{2}}$

$E_1= 45000\frac{N}{C}$

and the electric field generated by q2:

$E_2= k\frac{|q2|}{r_2^{2}} =(9.0\times10^{9}\,\frac{Nm^{2}}{C^{2}})\frac{|-6.0\times10^{-8}|}{(0.05)^{2}}$

$E_2=216000\frac{N}{C}$

Those are the magnitudes of the electric field, but electric field is a vector quantity, so the direction is important. Electric field generated by negative particles points towards the charge and electric field generated by positive particles points away the particle. So, if we define positive direction towards negative particle (x-axis):

$\overrightarrow{E_2}=+216000\frac{N}{C}\hat{i}$

$\overrightarrow{E_1}= +45000\frac{N}{C}\hat{i}$

Vector quantities satisfy superposition principle, this is $\overrightarrow{E}=\overrightarrow{E_1}+\overrightarrow{E_2}$ , with E the total electric field.

$\overrightarrow{E}=(216000+45000)\hat{i}=432000\frac{N}{C}\hat{i}$

b) The force is:

$\overrightarrow{F}=e*\overrightarrow{E}$ ,

with q the charge of an electron

$\overrightarrow{F}=(-1.61\times10^{-19})*(432000)\hat{i}=-6.92\times10^{-14}N\hat{i}$

8 0

3 years ago

The outside diameter of the playing area of an optical Blu-ray disc is 11.75 cm, and the inside diameter is 4.50 cm. When viewin

erica [24]

Answer:

The minimum angular speed 57.0 rad/s

Explanation:

In this exercise we must use the relationships between the angular and linear magnitudes, for the speeds we have

v = w r

As they give us that linear velocity is constant, we will calculate the angular velocity for the two radii, external and internal

r1 = 11.75 cm (1 m / 100cm) = 0.1175 m

w1 = v / r1

w1 = 6.70 / 0.1175

w1 = 57.0 rd / s

R2 = 4.50 cm = 0.0450 m

w2 = 6.70 / 0.0450

w2 = 148 rad / s

The minimum angular speed 57.0 rad / s

4 0

3 years ago