Solving using substitution Y=4 8x-y=-12

Mathematics

2 answers:

rusak2 [61]2 years ago

6 0

Plug y=4 into equaton
8x-4=-12
add 4 to both sides
8x=-8
divide both sides by 8
x=-1

x=-1
y=4
(-1,4)

Sophie [7]2 years ago

5 0

To solve this, you need to substitute the value of Y into the equation 8X - Y = -12

So, since Y = 4, plug 4 in for Y:

8X - Y = -12
8X - (4) = -12

Now solve for X.

Does that help? Do you have any questions?

Just as a heads up this technique also works for larger equations. If Y = 3X, then you'd just plug 3X in for Y:

8X - Y = -12
8X - (3X) = -12

You got this!

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