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zaharov [31]
3 years ago
13

Resolve to me these exercises please?

Mathematics
1 answer:
Dima020 [189]3 years ago
7 0
A)4^(n+3)=8^14
2^(2×(n+3))=2^(3×14)
2^(2n+6)=2^42
2^2n=2^36
n=18

b) (assuming a : is divide)
3^(2n+1)=9^17/3^3
3^(2n+1)=3^(2×16)/3^3
3^(2n+1)=3^29
3^2n=3^28
2n=28
n=14

d) (6^n)^4×36=216^10
6^4n×6^2=6^(3×10)
6^(4n+2)=6^30
6^4n=6^28
4n=28
n=7

e)7^(n^2)÷7=49^24
7^(n^2-1)=7^(2×24)
7^(n^2)=7^49
n^2=49
n=7

g)15^(n+4)÷5^(n+4)=81^6
3^(n+4)×5^(n+4)÷5^(n+4)=3^(4×6)
3^(n+4)=3^24
n=20

h)81^n÷9^n+9^(n+2)÷9=90÷9^6
9^2n÷9^n+9^(n+2)÷9=9*10/9^6
9^n+9^(n+1)=10/9^5
I don't know where to go from here

I)what?
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Rick has 1 1/3, or 4/3, pounds of sugar. 
He needs to pour 1/4 of this amount into the bowl.
4/3 * 1/4  Multiply the numerators and the denominators
(4*1) / (3*4) = 4/12                   Simplify, 4/12 can be simplified to 1/3. 
He poured 1/3 pound of sugar. 

Now, for flour, we need to find 1/4 of 2/3, using the same process:
(2/3) * (1/4) = (2*1) / (3*4) = 2/12 = 1/6
He poured 1/6 pound of flour 
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3 years ago
If 1/64=4^2s-1 times 16^2s+2 what is the value of s?
galina1969 [7]
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What is the solution set of this system of equations? y=x2−7 y=−x+5 The solution set of a system of equations is the set of all
iogann1982 [59]

Answer:

The answer to your question is (-4, 9) and (3, 2)

Step-by-step explanation:

Data

Equation 1    y = x² - 7

Equation 2   y = -x + 5

Process

1.- Substitute Equation 2 in equation 1

                    -x + 5 = x² - 7

2.- Equal to zero

                    x² + x - 7 - 5 = 0

                    x² + x - 12 = 0

3.- Factor to find x

                   (x + 4)(x - 3) = 0

                x₁ + 4 = 0        x₂ - 3 = 0

                x₁ = -4             x₂ = 3

4.- Substitute x₁ and x₂ to find y

                y = -x + 5        x₁ = -4

                y = -(-4) + 5

                y = 4 + 5

                y = 9            Solution (-4, 9)

                y = -x + 5         x₂ = 3

                y = -3 + 5

               y = 2            Solution (3, 2)

                     

             

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