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zaharov [31]
3 years ago
13

Resolve to me these exercises please?

Mathematics
1 answer:
Dima020 [189]3 years ago
7 0
A)4^(n+3)=8^14
2^(2×(n+3))=2^(3×14)
2^(2n+6)=2^42
2^2n=2^36
n=18

b) (assuming a : is divide)
3^(2n+1)=9^17/3^3
3^(2n+1)=3^(2×16)/3^3
3^(2n+1)=3^29
3^2n=3^28
2n=28
n=14

d) (6^n)^4×36=216^10
6^4n×6^2=6^(3×10)
6^(4n+2)=6^30
6^4n=6^28
4n=28
n=7

e)7^(n^2)÷7=49^24
7^(n^2-1)=7^(2×24)
7^(n^2)=7^49
n^2=49
n=7

g)15^(n+4)÷5^(n+4)=81^6
3^(n+4)×5^(n+4)÷5^(n+4)=3^(4×6)
3^(n+4)=3^24
n=20

h)81^n÷9^n+9^(n+2)÷9=90÷9^6
9^2n÷9^n+9^(n+2)÷9=9*10/9^6
9^n+9^(n+1)=10/9^5
I don't know where to go from here

I)what?
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maksim [4K]

Answer:

2(x - 3)(3x + 2)

Step-by-step explanation:

Given

6x² - 14x - 12 ← factor out 2 from each term

= 2(3x² - 7x - 6) ← factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 6 = - 18 and sum = - 7

The factors are - 9 and + 2

Use these factors to split the x- term

3x² - 9x + 2x - 6 ( factor the first/second and third/fourth terms )

= 3x(x - 3) + 2(x - 3) ← factor out (x - 3) from each term

= (x - 3)(3x + 2)

Thus

3x² - 7x - 6 = (x - 3)(3x + 2) and

6x² - 14x - 12 = 2(x - 3)(3x + 2) ← in factored form

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3 years ago
Examine the work shown. Explain the error and find the correct result.
Zepler [3.9K]

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dimaraw [331]
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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

s = d/t [ speed = distance/time]

therefor, rearranging, we get d = s x t

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