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Step2247 [10]
4 years ago
5

5^6/5^2

Mathematics
1 answer:
Sholpan [36]4 years ago
6 0

Answer:

3

Step-by-step explanation:

5 by 6 is 30 divided by 5 by 2

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What number should be added to –28 to make the sum 0?
Vesna [10]

Answer:28

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
I'll give brainiest to the first CORRECT answer PLS EXPLAIN.
kicyunya [14]

Answer:

The correct option is First. i.e <u>consistent.</u>

The System shown is <u>consistent.</u>

Step-by-step explanation:

Consistent:

A consistent system of equations is a system that has at least one solution.

Our System in graph has only and only ONE solution that is on X-axis

Where the lines are intersecting each other.

Hence, The System shown is <u>consistent.</u>

Inconsistent:

An inconsistent system of equations is a system that has no solution.

Equivalent:

Systems of equations that have the same solution are called equivalent systems. Given a system of two equations, we can produce an equivalent system by replacing one equation by the sum of the two equations, or by replacing an equation by a multiple of itself.

6 0
3 years ago
What is the answer for 3\5=a+5\25
IceJOKER [234]

Answer:

a = 2/5 = 0.400

Step-by-step explanation:

Step  1  :

           1

Simplify   —

           5

Equation at the end of step  1  :

 3          1

 — -  (a +  —)  = 0

 5          5

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Adding a fraction to a whole

Rewrite the whole as a fraction using  5  as the denominator :

         a     a • 5

    a =  —  =  —————

         1       5  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

a • 5 + 1     5a + 1

—————————  =  ——————

    5           5  

Equation at the end of step  2  :

 3    (5a + 1)

 — -  ————————  = 0

 5       5    

Step  3  :

           3

Simplify   —

           5

Equation at the end of step  3  :

 3    (5a + 1)

 — -  ————————  = 0

 5       5    

Step  4  :

Adding fractions which have a common denominator :

4.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 - ((5a+1))     2 - 5a

————————————  =  ——————

     5             5  

Equation at the end of step  4  :

 2 - 5a

 ——————  = 0

   5  

Step  5  :

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 2-5a

 ———— • 5 = 0 • 5

  5  

Now, on the left hand side, the  5  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  2-5a  = 0

Solving a Single Variable Equation :

5.2      Solve  :    -5a+2 = 0

Subtract  2  from both sides of the equation :

                     -5a = -2

Multiply both sides of the equation by (-1) :  5a = 2

Divide both sides of the equation by 5:

                    a = 2/5 = 0.400

One solution was found :

                  a = 2/5 = 0.400

Processing ends successfully

plz mark me as brailiest :)

4 0
3 years ago
Read 2 more answers
41:18
vazorg [7]

Answer:

I believe the answer is the 3rd choice witch would be c

4 0
3 years ago
The solution is {-8, 3} but I’m not sure how to graph it on a line, is it A B C or D?
shtirl [24]

Answer:

-8 < x< 3

Step-by-step explanation:

|2x+5| <11

there are two solutions, one positive and one negative ( remember to flip the inequality for the negative)

2x+5 <11  and   2x+5 > -11

Subtract 5 from each side

2x+5-5 < 11-5 and    2x+5-5 > -11-5

2x< 6           and           2x>-16

Divide by 2

2x/2 <6/2        and       2x/2 >-16/2

x <3                  and             x>-8

-8 < x< 3

x is less than 3 and x is greater than -8

open circles and -8 and 3 and a line between

8 0
3 years ago
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